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ziro4ka [17]
3 years ago
7

A kettle heats 1.75 kg of water. The specific latent heat of vaporisation of water is 3.34 x 106 J/kg. How much energy would be

needed to boil off the water? Write the answer out in full (i.e. not in standard form).
Physics
1 answer:
labwork [276]3 years ago
7 0

The amount of energy needed to boil off the water is 5,845,000 J

Explanation:

The amount of thermal energy needed to completely boil a certain amount of a liquid substance already at boiling temperature is given by

Q=m\lambda_v

where

m is the amount of the substance

\lambda_v is the specific latent heat of vaporization of the substance

In this problem, the substance is water, and its mass is

m = 1.75 kg

Its specific latent heat of vaporization is

\lambda_v = 3.34\cdot 10^6 J/kg

Assuming that the water is already at boiling temperature, therefore, the thermal energy needed to boil off the water is

Q=(1.75)(3.34\cdot 10^6)=5,845,000 J

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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Complete Question

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Answer:

Explanation:

From the question we are told that

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        The extension of the web is  e=  4.00 \ mm = 0.004 \ m

       

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substituting values

       f =  \frac{1}{2 * 3.142 } \sqrt{\frac{0.027}{1.1*10^{-5}} }

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3 years ago
The half-life of the radioactive isotope Carbon-14 is about 5730 years. Find N in terms of t. The amount of a radioactive elemen
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Explanation:

Given

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A(t) =A₀e ^kt

such that

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Dividing both sides by A₀

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1/2 = e ^k(5730)

1/2 = e^5730K

In 1/2 =  5730K

k = 1n1/2 / 5730

k = 1n0.5 / 5730

K= -0.00012 = 1.2 X 10^-4

So that expressing   N in terms of t, we have

A(t) =A₀e ^kt

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Danny lowers the sails on his boat. He paddles upstream at 19 km/hr. The current is still running downstream at 15 km/hr. What i
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A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed
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Answer:

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Explanation:

A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed of the rock at 2m on the way down compare with its speed at 2m on the way up?

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