Answer:
Part 1)
-------> 
Part 2)
--------> 
Part 3)
------> 
Part 4)
------> 
Step-by-step explanation:
Part 1) we have

To calculate the division problem convert the decimal number to fraction number
so

Remember that
Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Simplify
Divide by 22 both numerator and denominator

Part 2) we have

To calculate the division problem convert the mixed number to an improper fraction

so

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Convert to mixed number

Part 3) we have

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Simplify
Divide by 5 both numerator and denominator

Part 4) we have

To calculate the division problem convert the mixed number to an improper fraction

so

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

Answer:
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Step-by-step explanation:
Answer:
B)blocks in 5th row=15+(5-1)(-2)
Step-by-step explanation:
We are given that
Number of block in bottom row=15
Each row has 2 fewer blocks than the previous row
We have to find the formula would you use to find the number of blocks in the 5th row.
Number of blocks in second row=15-2=
Number of blocks in third row=15-2-2=
Number of blocks in 4th row=
Number of blocks in 5th row=
Therefore, number of block in 5th row

This is required formula to find the number of blocks in the 5th row
Hence, option B is true.
B)blocks in 5th row=15+(5-1)(-2)
Answer:
y=-3x+6
Step-by-step explanation:
that equation gives the answer for all the 'y'
Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation: