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3 years ago

Amplitude of y=-3sin5x

Mathematics

2 answers:

GaryK [48]3 years ago

4 0

Answer:

Amplitude is 3

Step-by-step explanation:

in y=-3sin5x

the number in front of sign is always the amplitude. Its not negative 3 because the negative simply means it reflects across the x-axis

tiny-mole [99]3 years ago

4 0

ANSWER

The amplitude is 3

EXPLANATION

The amplitude of a periodic function is the distance from the midline of its graph to the peak.

The given function is:

$y = - 3 \sin(5x)$

This function is of the form:

$y = a \: \sin(bx)$

The of this function is

$|a|$

By comparing the two functions, we have a=-3.

Therefore the amplitude of the given function is

$| - 3| = 3$

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Drag the tiles to the correct boxes to complete the pairs.

Ne4ueva [31]

Answer:

Part 1) $-1.25$ -------> $2.75/(-2.2)$

Part 2) $-4\frac{1}{3}$ --------> $(-2\frac{3}{5}) / (\frac{3}{5})$

Part 3) $\frac{2}{3}$ ------> $(-\frac{10}{17}) / (-\frac{15}{17})$

Part 4) $3$ ------> $(2\frac{1}{4}) / (\frac{3}{4})$

Step-by-step explanation:

Part 1) we have

$2.75/(-2.2)$

To calculate the division problem convert the decimal number to fraction number

$2.75=275/100\\ -2.2=-22/10$

$(275/100)/(-22/10)$

Remember that

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(275/100)/(-22/10)=(275/100)*(-10/22)=-(275*10)/(22*100)=-(275)/(220)$

Simplify

Divide by 22 both numerator and denominator

$-(275)/(220)=-125/100=-1.25$

Part 2) we have

$(-2\frac{3}{5}) / (\frac{3}{5})$

To calculate the division problem convert the mixed number to an improper fraction

$(-2\frac{3}{5})=-\frac{2*5+3}{5}=-\frac{13}{5}$

$(-\frac{13}{5}) / (\frac{3}{5})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{13}{5}) / (\frac{3}{5})=(-\frac{13}{5})*(\frac{5}{3})=-\frac{13*5}{5*3}=-\frac{13}{3}$

Convert to mixed number

$-\frac{13}{3}=-(\frac{12}{3}+\frac{1}{3})=-4\frac{1}{3}$

Part 3) we have

$(-\frac{10}{17}) / (-\frac{15}{17})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{10}{17}) / (-\frac{15}{17})=(-\frac{10}{17})*(-\frac{17}{15})=\frac{10*17}{17*15}=\frac{10}{15}$

Simplify

Divide by 5 both numerator and denominator

$\frac{10}{15}=\frac{2}{3}$

Part 4) we have

$(2\frac{1}{4}) / (\frac{3}{4})$

To calculate the division problem convert the mixed number to an improper fraction

$(2\frac{1}{4})=\frac{2*4+1}{4}=\frac{9}{4}$

$(\frac{9}{4}) / (\frac{3}{4})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(\frac{9}{4}) / (\frac{3}{4})=(\frac{9}{4})*(\frac{4}{3})=\frac{9*4}{4*3}=\frac{9}{3}=3$

8 0

3 years ago

Plz help me. answer all these questions.

Greeley [361]

Answer:

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Step-by-step explanation:

6 0

3 years ago

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A child building a tower with Blocks uses 15 for the bottom row. Each row has 2 fewer blocks than the previous row. What formula

xenn [34]

Answer:

B)blocks in 5th row=15+(5-1)(-2)

Step-by-step explanation:

We are given that

Number of block in bottom row=15

Each row has 2 fewer blocks than the previous row

We have to find the formula would you use to find the number of blocks in the 5th row.

Number of blocks in second row=15-2= $15+1(-2)$

Number of blocks in third row=15-2-2= $15+2(-2)$

Number of blocks in 4th row= $15-2-2-2=15+3(-2)$

Number of blocks in 5th row= $15-2-2-2-2=15+4(-2)$

Therefore, number of block in 5th row

$15+(5-1)(-2)$

This is required formula to find the number of blocks in the 5th row

Hence, option B is true.

B)blocks in 5th row=15+(5-1)(-2)

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3 years ago

A function is shown in the table below. What equation represents this function?

den301095 [7]

Answer:

y=-3x+6

Step-by-step explanation:

that equation gives the answer for all the 'y'

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3 years ago

A school wishes to form three sides of a rectngular playground using 480 meters of fencing. The playground borders the school bu

nirvana33 [79]

Answer

school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in

terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters

Step-by-step explanation:

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3 years ago

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