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kotykmax [81]
3 years ago
11

Please help with 2 questions thank you!

Mathematics
1 answer:
yarga [219]3 years ago
3 0
Question 1:
The triangle on the left and the triangle on the right are congruent by ASA (or SAS).
Now, you just have to match them.

After matching the corresponding congruent parts, you get
VTU = ABC

Your answer is the second choice.

Question 2:
You have two right triangles.
You also have a pair of congruent hypotenuses.
And you have a shared side.
The two triangles are congruent by HL.

Your answer is the second choice.

Have an awesome day! :)
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29

Step-by-step explanation:

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5x+35=180

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1  or \frac{2}{2}

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Select the correct answer.
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URGENT ANSWER NOW In △ABC, A=59∘, a=20, and c=21. What are the two possible values for angle C to the nearest tenth of a degree?
PilotLPTM [1.2K]

Answer:

The two possible values of C are 64.2° and 115.8°

Step-by-step explanation:

* In ΔABC

- a, b, c are the lengths of its 3 sides, where

# a is opposite to angle A

# b is opposite to angle B

# c is opposite to angle C

- m∠A = 59°

- a = 20

- c = 21

* To find the distance m∠C we can use the sin Rule

- In any triangle the ratio between the length of each side

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- c/sinC = a/sinA = b/sinB

* Lets use it to find the m∠C

∵ 21/sinC = 20/sin(59)

∴ sin(C) = 21 × sin(59) ÷ 20 = 0.9000256657

∴ m∠C = sin^-1(0.9000256657)  = 64.16144°

∴ m∠C = 64.2°

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∴ The other measure of ∠C = 180 - 64.2 = 115.8

* The two possible values of C are 64.2° and 115.8°

6 0
3 years ago
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