50(115-y) + 25y = 4125 [from eq2]
5750 - 50y + 25y = 4125 [distribute]
5750 - 25y = 4125
-25y = -1625
y = 65 [divide both sides by (-25)]
There are 65 small boxes.
Put that value into either equation (now, which is easier?) to solve for x:
x = 115 - y
x = 115 - 65
x = 50
There are 50 large boxes.
Answer:
The distance of the overpass above the ground is approximately 26.795 ft
Step-by-step explanation:
The parameters given are;
The distance from the overpass the engineer stands before determining the angle of elevation of the overpass from his standing point = 100 ft
The angle of elevation of the overpass as determined by the engineer from 100 ft = 15°
By trigonometric ratios, we have;
The opposite side to the 15° angle of elevation in the above case is the distance of the overpass above the ground
The opposite side to the 15° is the distance of the engineer from the base of the overpass
Therefore;
Tan(15°) the height of the overpass=
length
The distance of the overpass above the ground = 100 × tan (15°) ≈ 26.795 ft.
Answer:
She can create a function for the total savings in terms of the time x by adding the two functions together. The new function should look like this:
T(x)=S(x)+a(x)
So now we can substitute the given functions:
T(x)=450+6(x-2)
But this function can be simplified for it to be easier for her to calculate her total amount of savings. We can do that by distributing the 6 into the parenthesis. This is, multiply the 6 by both the x and the -2, so we get:
T(x)=450+6x-12
and now we can combine like terms. We can subtract 12 from 450 so we get:
T(x)=6x+438
And that will be our final function.
18/3.5=5.1 so you do 14/5.1=2.7
so your answer is 2.7 in
121/150 or 0.0806. The 6 is repeating itself.
