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lianna [129]
4 years ago
11

What is -3x+2c=-3,for x

Mathematics
1 answer:
patriot [66]4 years ago
3 0
X = 2/3c -1 ...........
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Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = (x2 − 1)3, [−1, 2]
Alja [10]

Given :

F(x)=3(x^2-1)

To Find :

the absolute minimum and absolute maximum values of f on the given interval

[-1,2] .

Solution :

Now , getting first order differential equation and equating its equal to zero.

\dfrac{d(3x^2-3)}{dx}=0\\\\6x=0\\x=0

So , x=0 is critical point .

Now , coefficient of x^2 is positive .

Therefore , it is increasing function after  x=0 .

So , min value will be at , x=0.

Min = (0^2-1)\times 3=-3

And maximum value will be the maximum at the x=2 because it is increasing function .

Max=(2^2-1)\times 3=9

Therefore , max and min value is 9 and -3 respectively .

Hence , this is the required solution .

3 0
3 years ago
How to solve this equation <br> y=-2+6 and 3y-x+3=0
nikitadnepr [17]
Y=0 and x=3 there that's what I got

8 0
4 years ago
36 is 0.09% of what number
alexgriva [62]
Х-100%
36-0,06%
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Answer:60000
8 0
3 years ago
16r^4t-6r^3t^2+4rt^2=
DochEvi [55]

Answer:

2rt(8r^3-3r^2t+2t)

Step-by-step explanation:

We have been given a polynomial 16r^4t-6r^3t^2+4rt^2 and we are supposed to simplify our polynomial.

We will use factoring to simplify our polynomial. Let us factor out the greatest common factor of all the terms.

We can see that 16, 6 and 4 has 2 as their greatest common factor.

The greatest common factor of r^4, r^3,r is r.

The greatest common factor of t, t^2, t^2 is t.

So the greatest common factor of the terms of our expression will be 2rt.

Let us factor out 2rt from our given polynomial.

2rt(8r^3-3r^2t+2t)

As we can not factor our expression more, therefore, we will get 2rt(8r^3-3r^2t+2t) after simplifying our polynomial.

5 0
3 years ago
Need help solving this ASAP
avanturin [10]

Answer:

i got 279

Step-by-step explanation:

7 0
3 years ago
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