Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =

Mathematics

2 answers:

ra1l [238]4 years ago

7 0

Answer:

Step-by-step explanation:

5 is correct, since (CE)(ED) = (AE)(EB).

Vitek1552 [10]4 years ago

5 0

So here is how we are going to find out what is ED.
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5.
Hope this answer helps. Let me know if you need more help next time!</span>

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The zero-product principle states that if AB = 0, then

s2008m [1.1K]

A = 0 (or) B = 0

Solution:

The zero product principle is most probably used to solve a quadratic equation by factoring the factors.

Let us know the definition of zero product principle.

Zero product principle:

The zero product principle states that if the product of two factors is zero then at least one of the factors must be zero.

This means that if AB = 0, then A = 0 (or) B = 0.

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8 0

3 years ago

2x^{3}+30xx^{2} +72x=0 solve using zero product property

Goshia [24]

Answer:

Values of x are: x=0 or x=-3 or x=-12

Step-by-step explanation:

The equation given to solve using zero product property is $2x^3+30x^2+72x=0$

Zero property rule states that if ab=0 then a=0 or b=0

Taking x common from the equation:

$2x^3+30x^2+72x=0\\x(2x^2+30x+72)=0\\$

Applying zero product rule

$x(2x^2+30x+72)=0\\x=0 \ or \ 2x^2+30x+72=0$

Now, solving $2x^2+30x+72=0$

Using quadratic formula to find value of x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Putting values

$$x=\frac{-30\pm\sqrt{(30)^2-4(2)(72)}}{2(2)}$\\$x=\frac{-30\pm\sqrt{324}}{4}$\\$x=\frac{-30\pm18}{4}$\\$x=\frac{-30+18}{4} \ or \ x=\frac{-30-18}{4}$ \\x=-3 \ or \ x=-12$