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2 years ago

Help my brain is on life support isnt it 2 to the power of 6

Mathematics

2 answers:

tatiyna2 years ago

5 0

$2^{6}$

When you have powers in this fashion, all we need to do is multiply the two to get our answer.

Now we can solve:

2 x 2 x 2 x 2 x 2 x 2

4 x 4 x 4

16 x 4

I hope this helps! :)

maxonik [38]2 years ago

4 0

Yes it is I took the test and it said it was wrong but others got it right.

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If a family uses 3 gallons of milk every week, how much milk will this family use in four days?

geniusboy [140]

Answer:

Step-by-step explanation:

3 gallons of milk in 1 week means they use 3 gallons of milk in 7 days.

To find out how much milk they use in 1 day, simply divide 3 gallons by 7.

1 day = 3/7 gallons

Then to find how much they use in 4 days, multiply the amount in 1 day by 4.

4 days = 3/7 x 4 = ? Gallons

6 0

3 years ago

Read 2 more answers

No link answers please!!

nignag [31]

Answer: X= 6 or X=-4

Step-by-step explanation:

$x^{2} -2x-24=0\\(x-6)(x+4)=0\\x-6=0 --> x=6\\x+4=---> x=-4$

8 0

3 years ago

A dealer gained a 10% profit by selling an article for Birr 330.00. what was original price of the article

astraxan [27]

Answer:

???????

Step-by-step explanation:

6 0

3 years ago

Consider the following region R and the vector field F. a. Compute the two-dimensional curl of the vector field. b. Evaluate bo

Shalnov [3]

Looks like we're given

$\vec F(x,y)=\langle-x,-y\rangle$

which in three dimensions could be expressed as

$\vec F(x,y)=\langle-x,-y,0\rangle$

and this has curl

$\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle$

which confirms the two-dimensional curl is 0.

It also looks like the region $R$ is the disk $x^2+y^2\le5$ . Green's theorem says the integral of $\vec F$ along the boundary of $R$ is equal to the integral of the two-dimensional curl of $\vec F$ over the interior of $R$ :

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA$

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of $R$ by

$\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle$

$\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt$

with $0\le t\le2\pi$ . Then

$\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt$

$=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0$

7 0

3 years ago

3) Last year Kerry’s take home pay was £15 000 She spent 40% of her take home pay on rent. She used the rest of her take home pa

gregori [183]

3,000. You take 15,000 and multiply by .4 to get how much she spent on rent (6,000). They you subtract the rent money from her total pay to get her money that she spent on living expenses, clothes and entertainment in total (9,000). Since she spent her money in six parts (3+2+1), you divide 9,000 by 6 to get 1,500 to get each part. Since for entertainment she has two parts you multiply 1,500 by 2 to get 3,000.

4 0

3 years ago