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alexdok [17]
3 years ago
5

A supplier of instrument gauge clusters uses a kanban system to control material flow. The gauge cluster housings are transporte

d five at a time. A fabrication center produces approximately 10 gauges per hour. It takes approximately two hours for the housing to be replenished. Due to variations in processing times, management has decided to keep 20 percent of the needed inventory as safety stock. How many kanban card sets are needed? (Round up your answer to the nearest whole number.)
Number of kanban card sets ?
Business
1 answer:
Inessa [10]3 years ago
3 0

Answer: 2 kanban card sets will be needed.

Explanation: 20% of 10 gauges gives the safety inventory stock.

This will be 20/100 ×10=2

But 10 gauges are produced per hour out of which 2 will be kept as safety inventory stock, making it to be 10-2=8gauges per hour.

Number of kanban cards used for transporting gauges 8/5=1.6

1.6= 2to the nearest whole number.

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Midwest Water Works estimates that its WACC is 10.5%. The company is considering the following capital budgeting projects:
krok68 [10]

Answer:

Projects A,B,C,D and E should be accepted

Explanation:

Based on the fact that each of the itemized projects has the same of level of risk as the company's existing assets, we suggest that the firm undertake those projects that gives a return rate which is above the current weighted average cost of capital of 10.5%

In essence,projects A,B,C,D and E should be accepted as they 12%,11.5%,11.2%,11% and 10.7% returns on investment respectively.

Projects F& G would be rejected on the premise that their rates of return are lower than what is currently obtainable in Midwest Water Works.

7 0
3 years ago
Which of the following assessments of electronic retailing is most accurate? a. The line between electronic retailing and tradit
IgorC [24]

Answer:

The correct answer is letter "A": The line between electronic retailing and traditional retailing is blurring as traditional retailers go online.

Explanation:

Most purchases nowadays are being processed online. The easiness to access to a wide variety of products and the methods of payments causes more people to buy online. Besides, the number of retailer stores with mobile apps is increasing so there is no need to have a computer to make the purchases online since they can be made with a phone. This scenario is fading the line that used to separate traditional retailing with online retailing.

4 0
4 years ago
Diana owns a bakery where she sells cupcakes. Two blocks down there is another bakery, CC's Bakery, that sells cupcakes for $1 l
elena-14-01-66 [18.8K]

Answer:

competitor-oriented pricing

Explanation:

competitor-oriented pricing is a technique for valuing in which a producer's value is resolved more by the cost of a comparable item sold by an incredible contender than by contemplation of purchaser request and cost of generation; likewise alluded to as Competition-Based Pricing.  

For instance: a firm needs to value another espresso producer. The company's rivals sell it at $25, and the organization thinks about that the best cost for the new espresso producer is $25. It chooses to set this very cost without anyone else item.

3 0
3 years ago
When will diversity affect the workplace?
DochEvi [55]
It already does affect the workplace.
8 0
3 years ago
Read 2 more answers
A flying squid (family Ommastrephidae) is able to "jump" off the surface of the sea by taking water into its body cavity and the
Zielflug [23.3K]

Answer: V=7.43m/s

d =2.82m

Explanation:

a) For the first part, the initial velocity immediately after ejection, by using momentum conservation

before ejection, the momentum of the squid/water system is zero

there are no external forces acting on the system at the moment of ejection, so we can find the speed of the squid by noting

momentum before ejection = momentum after ejection

0 = M1U + M2V

0=-0.26 kg x 20 m/s + 0.7kg x V

where the speed of the water is taken as the negative sign, and V is the speed of the squid right after ejection, solving for V we get

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B. we use the equation vf^²=v0^²+2ad

where vf=final velocity = 0 since velocity is zero at motion's apex

v0=initial velocity = 7.43m/s

a = acceleration = -9.8m/s/s

d=height (to be found)

Therefore,

0=7.43^²+2(-9.8)d

Mathematically, it becomes

d=7.43^²/2(9.8)= 2.82m

d = 2.82m

4 0
4 years ago
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