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3 years ago

What is the difference 5/8 - 3/4 = 5/8 - 6/8 = ______ HELP ME FAST

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

8 0

Answer:

There is no difference/they are the same

Step-by-step explanation:

5/8 is the same as 5/8

3/4 is the same as 6/8

3 *2 = 6

__ _

4*2 = 8

(2/2 = 1)

romanna [79]3 years ago

3 0

Answer:
- 1/8
Step-by-step explanation:
5/8 - 6/8
Just consider the numerators (exclude the 8's),
5 - 6 = -1
Now substitute it with the same denominator 8.
-1/8

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The perimeter of a square is 36 feet. If you increase the length by 3 feet and decrease the width

Rufina [12.5K]

Answer:

84 feet

Step-by-step explanation:

If the perimeter is 36 feet, and all the sides are the same length, then all the sides are 9. if we increase the length by 3 feet and decrease the width by 2 feet then we are left with 12 * 7 = 84

4 0

3 years ago

c) The GCF and LCM of two numbers are 2 and 70 respectively. If one of the numbers is 10, find the other number? [3m] solution:

Mice21 [21]

Their LCM is

hope it helps you.

8 0

2 years ago

There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con

grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

$\square ABCD$

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$

$\angle BAC = \angle DCA$

Required

Which theorem shows △ABE ≅ △CDE.

From the question, we understand that:

AC and BD intersects at E.

This implies that:

$\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$

and

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$

So, the congruent sides and angles of △ABE and △CDE are:

$\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD$ ---- S

$\angle BAC = \angle DCA$ ---- A

$\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED$ or $\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC$ --- S

Hence, the theorem that compares both triangles is the SAS theorem

4 0

2 years ago

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

Multiplying both sides by 16 we get:

$256=3x^2$

Dividing both sides by 3 we get:

$\frac{256}{3} =x^2$

Using square root on both sides we get:

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

So, the base of triangle = $\frac{8}{\sqrt{3}} \ m.$

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

Thus, the height of triangle = $\frac{12}{\sqrt{3}} \ m.$

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago

The exponential decay graph shows the expected depreciation for a new boat, sell g for $3500, over 10 years.

Alisiya [41]

Okay, the exponential function is
$g = a^{x}$
The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes
$g = 3500^{x}$
Let's see at t=2, where the price is g=2000:
$2000 = 3500^{x}$
Take natural logarithm:
$ln 2000 = ln 3500^{x}$
$x*ln 3500 = ln 2000$
$x = \frac{ln 2000}{ln 3500} = 0.93$
So, the difference between t=0 and t=2 is
$x_{t=0} - x_{t=2} = 1 - 0.93 = 0.07$
And then we get the change of x in one year equal to 0.035.
So, the final equation is
$g = 3500^{1-0.035t}$
You can insert any t and see that it is correct, for example t=7

8 0

3 years ago