To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75
The answer is 0, as there is no slope going up or down.
9514 1404 393
Answer:
no
Step-by-step explanation:
Put 2 where x is and see if you get a true statement.
1/2(2) -4 = 5
1 -4 = 5
-3 = 5 . . . . . . False
2 is not a solution to the equation.
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The solution is x=18.
Answer:
x = 
, y = 
Step-by-step explanation:
1. Isolate for x in one of the equations:
2x = 9x - 14y
2x-9x = 9x-9x -14y
-7x = -14y
-7x/-7 = -14y/-7
x = 2y
2. Substitute 2y in for x in the second equation:
9(2y) = 40 - 14y
3. Simplify:
18y = 40 - 14y
4. Isolate for y:
18y+14y = 40 -14y+14y
32y = 40
32y/32 = 40/32
y =
5. Substitute the new y-value into the simplified expression x = 2y:
x = 2(5/4)
x =
hope this helps!
