Using an indirect proof:
Assume that the figure is a trapezoid.
All trapezoids are quadrilaterals.
All quadrilaterals' interior angles add up to 360° because any n-gon's interior angles add up to 180(n-2)°.
We are given that the trapezoid has three right angles.
All right angles are 90°, thus these right angles have a total measure of 270°.
We can conclude fourth angle must be 90°.
If it has four right angles, it is a rectangle.
Rectangles have two sets of parallel sides.
However, trapezoids have exactly one set of parallel sides.
Alas, our figure cannot be a trapezoid.
To find surface area, you would find the area of each side of the shape. Since this is a cube, each side is a square. So area=side2, So each side is 9, so 9x9=81 for each face. There are 6 faces to a cube, so 6x81=486 in2 is your answer
P(> or =70) =0.65
P(Collins inside) =0.80
P(not 70) = 1-P(70) =>0.35
P(Collins inside) = 0.1
Then P(70 AND Collin inside) .65 x .8 =0.52
P( not 70 AND Collin Outside = 0.35 x 0.1=0.035
TOTAL Possibility [(70 AND Inside) OR (not 70 AND Outside):
=0.52 + 0.034 =0.555
Answer:it didnt
Step-by-step explanation: