X is 35. 180=75+3x. 180-75/3=35
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)
We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>
The vector product pq x pr gives a vector perpendicular to both pq and pr. This vector is the normal vector of a plane passing through all three points
pq x pr
=
i j k
-4 -2 -4
-3 5 1
=<-2+20,12+4,-20-6>
=<18,16,-26>
Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>
The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).
The equation of the required plane is therefore
Π : 9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π : 9x+8y-13z=24
Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.
Answer:
Hypotenuse = 14.1421 inches (rounded off to four decimal values)
Step-by-step explanation:
The legs of an isosceles triangle both measure 10 inches
Since the triangle is a right triangle,
We apply the Pythagorean Theorem to find the height of the hypotenuse
a² + b² = c²
a = 10 inches, b = 10 inches and (c) is the hypotenuse whose value we don't know.
So; 10² + 10² = c²
c² = 100 + 100
c² = 200
c =
= 14.1421356237 inches
The hypotenuse is 14.1421 inches (answer rounded off to four decimal values)
So, let's say that all the dogs had a number of x.
then 1/12 x were the Hound Group dogs.
then, out of the Hound Group,, that is 1/12 x, 3/10 were English Foxhounds.
For this, we need to multiply the fractions:
![\frac{1}{12}x* \frac{3}{10} = \frac{3}{120}x =\frac{1}{40}x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B12%7Dx%2A%20%5Cfrac%7B3%7D%7B10%7D%20%3D%20%5Cfrac%7B3%7D%7B120%7Dx%20%3D%5Cfrac%7B1%7D%7B40%7Dx%20%20)
so of all the dogs at the show, the English Foxhunds were a 1/40 fraction,