Answer:
The correct answer is "negative".
Explanation:
At pH 2 the net charge of the R groups of all the amino acids that comprise the peptide in question would be positive. This happens because of the high content of protons in a solution of pH 2, a value that is below the isoelectric point of all the amino acids. Since the peptide would have a positive net charge, it would migrate to the negative terminal of the gel because opposite charges attract each other.
The answer for this question would be choice <span>B) Water, rock, and surface materials, or the second option.</span>
More growth of flowers and or more plant food/water supply for it
Answer:
very few M. tuberculosis in the standard nutrient cell cultures carry the rpoB gene mutation, but almost all of the M. tuberculosis in the cell cultures with rifampin carry the rpoB mutation
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.