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AlladinOne [14]
3 years ago
8

An atom emits a photon with energy 7.13 electronvolts (eV). What is the wavelength of the photon?

Chemistry
1 answer:
sergey [27]3 years ago
5 0

Answer:

Option (b) "174 nm"

Explanation:

Energy of emitted photon is 7.13 eV.

We need to find the wavelength of the photon.

1 eV = 1.6 × 10⁻¹⁹ J

Energy of a photon is given by :

E=\dfrac{hc}{\lambda}

Where, \lambda is wavelength of the photon

Putting all the values,

\lambda=\dfrac{hc}{E}\\\\\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{7.13\times 1.6\times 10^{-19}}\\\\\lambda=1.74\times 10^{-7}\ m\\\\\text{or}\\\\\lambda=174\ nm

So, the wavelength of the photon is 174 nm.

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In Lewis dot structures, you draw the atom in the center and then surround the atom with its valence electrons. The Lewis structure for O is as shown in the attached diagram.

<h3>What is the Lewis structure of O ?</h3>

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uysha [10]

Answer:

The answer is: <u>Al2O3</u>

Explanation:

The data they give us is:

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To find the empirical formula without knowing the grams of the compound, we find it per mole:

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Then we must divide the results obtained by the lowest result, which in this case is 0.02:

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