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OLEGan [10]
2 years ago
13

calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w

ater and the normal boiling point of water the molar entropy change accompanying fussion is 22.0 and that accompanying evaporation
Chemistry
1 answer:
kipiarov [429]2 years ago
6 0

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is -22Jmole^-^1k^-^1

(b) The normal boiling point of water (J·K−1·mol−1) is -109Jmole^-^1K^-^1

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is  109J/mole

Explanation:

Lets calculate

(a) - General equation -

      (\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p = -5_m(\beta )+5_m(\alpha ) =  -\frac{\Delta H}{T}

 \alpha ,\beta → phases

ΔH → enthalpy of transition

T → temperature transition

 (\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p == -\frac{\Delta_fH}{T_f}

            = \frac{-6.008kJ/mole}{273.15K} ( \Delta_fH is the enthalpy of fusion of water)

           = -22Jmole^-^1k^-^1

(b) (\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}

                                  = \frac{40.656kJ/mole}{373.15K} (\Delta_v_a_p_o_u_rH is the enthalpy of vaporization)

                               = -109Jmole^-^1K^-^1

(c) \Delta\mu =\Delta\mu(l)-\Delta\mu(s) =-S_m\DeltaT

[\mu(l-5°C)-\mu(l,0°C)] =  [\mu(s-5°C)-\mu(s,0°C)]=-S_mΔT

\mu(l,-5°C)-\mu(s,-5°C)=-Sm\DeltaT [\mu(l,0

\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)

     = 109J/mole

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3 years ago
1. For each of the following, convert the word equation into a formula equation, BUT do not balance! (4 pts each = 12 pts)
daser333 [38]

Answer:

  • 1a) BaClO₃(s) → BaCl₂(g) + O₂(g)

  • 1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

  • 1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

  • 2a) Calcium hydroxide and hydrogen gas

  • 2b) Tin(II) silicate and Lead(IV) permanganate

  • 2c) Magnesium oxide and water

  • 2d) No product

  • 2e) Mercury and iodine

  • 2f) Calcium chloride and iodine

  • 2g) Strontium phosphite and cesium nitride

  • 2h) Carbon dioxide, water, and sulfur dioxide

  • 2i) Iron oxide(III) and carbon dioxide

  • 2j) Magnesium acetate and hydrogen gas

  • 2k) Calcium iodide

Explanation:

1. For each of the following, convert the word equation into a formula equation, BUT do not balance!

a) Barium chlorate → Barium chloride + Oxygen

<u>1. Chemical formulas</u>

Barium chlorate:

  • It is a salt: an ionic compound.
  • Barium has oxidation state +2
  • Chlorate is the ion ClO₃⁻
  • Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
  • Chemical formula Ba(ClO₃)₂
  • It is solid: Ba(ClO₃)₂(s)

Barium chloride:

  • It is a salt: an ionic compount
  • Barium has oxidation state +2
  • Chlorine is in oxidation state -1
  • Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
  • BaCl₂
  • It is solid BaCl₂(s)

Oxygen:

  • It is a diatomic gas molecule
  • O₂(g)

<u />

<u>2. Write the unbalanced molecular equation:</u>

  • BaClO₃(s) → BaCl₂(s) + O₂(g)

b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride

<u>1. Chemical formulas</u>

Chlorine:

  • It is a diatomic gas molecule
  • Cl₂(g)

Potassum nitride

  • It is a salt
  • Potassium has oxidation state +1
  • Nitrogen is with oxidation state +3
  • Swap the oxidation states
  • K₃N
  • It is solid: K₃N(s)

Nitrogen:

  • It is a diatomic gas
  • N₂(g)

Potassium chloride

  • It is a salt (ionic compound)
  • Potassium has oxidation state +1
  • Chlorine is in oxidation state -1
  • Swap the oxidation numbers
  • KCl
  • It is solid: KCl(s)

<u>2. Write the unbalanced molecular equation</u>

<u />

  • Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate

<u>1. Chemical formulas</u>

Sodium nitride

  • It is a salt (ionic compound)
  • Sodium has oxidation state +1
  • Nitrogen is with oxidation state -3
  • Swap the oxidation numbers
  • Na₃N
  • It is in aqueous solution
  • Na₃N (aq)

Aluminum bromate

  • Salt
  • Aluminum has oxidation state +3
  • Bromate is the ion BrO₃⁻
  • Swap the oxidation states
  • Al(BrO₃)₃ (aq)

Aluminum nitride

  • Both Al and N have oxidation state 3, which simply
  • AlN(s). It is not soluble in water.

Sodium bromate

  • Na(BrO₃)₃ (aq)

<u>2. Write the unbalanced molecular equation</u>

  • Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

<h2>This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2></h2><h2>The attached file contains the complete answer.</h2>
Download pdf
4 0
3 years ago
What is the Density of 85 mL of a liquid that has a mass of 54 Kg?
Korolek [52]

Answer:

The answer to your question is  density = 635.3 g/ml (check the units)

Explanation:

Data

density = ?

volume = 85 ml

mass = 54 kg

Density is a physical property that relates the mass of an object and its volume.

The unit of this property are g/ml or kg/m³

In this problem, I will calculate the density in g/ml

Formula

            density = mass/ volume

-Substitution

            density = 54000 / 85

-Simplification

            density = 635.3 g/ml

3 0
3 years ago
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