The answer to the mathematics question presented above is 'True'. It is correct to say that in (r theta), the value of r can be negative. A negative radius can be used when it comes to graphing a "polar'' function. Thus, the answer to the question is 'true'.
Answer:

Step-by-step explanation:
Given

Required
Approximate (to the nearest 100th)
This means that, we approximate at the second digit after the decimal.
So:
i.e,
Number = 39.79 [Begin approximation] 949748
The first digit after [Begin approximation] is then approximated using the following rule:


Since 9 falls in
category, the number becomes:
![Number = 39.[79+1]](https://tex.z-dn.net/?f=Number%20%3D%2039.%5B79%2B1%5D)

If 3 = (b x 3)
C. 1
Substitute b for the answer choices so
9 x 3 = 27
6 x 3 = 18
1 x 3 = 3
0 x 3 = 0
Answer:
First off, I can't solve for y, there is no y variable.
Second, 3 = 7 ( 1 - 1 ) is not true because 3 ≠ 0 ( 3 doesn't equal 0 ) :
3 = 7 ( 1 - 1 )
3 = 7 ( 0 ) ( Simplify Parenthesis )
3 = 0 ( Multiply 7 and 0 )
3 ≠ 0