My answer is the 2nd option.
Without changing the compass setting from the previous step, place the compass on point P. Draw an arc similar to the one already drawn.
Parallel lines are lines that do not meet. In this figure, point P is the point where the 2nd line can be drawn and become parallel to line AB.
Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation
Solve for S(t):
The left side is the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5Be%5E%7Bt%2F800%7DS%28t%29%5Cright%5D%3D%5Cdfrac8%7B100%7De%5E%7Bt%2F800%7D)
Integrate both sides:
There's no sugar in the water at the start, so (a) S(0) = 0, which gives
and so (b) the amount of sugar in the tank at time t is
As 
, the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
Answer:
Number of pineapples = 10
Number of pears = 10 + 9 = 19
Number of kiwis = 10 - 2 = 8
Step-by-step explanation:
Money = $ 13.5
Cost of a pear = $ 0.5
Cost of a pineapple = $ 1.5
Cost of a kiwi = $ 0.3
let the number of pineapple = p
Number of pears = p + 9
Number of kiwis = p - 2
Cost is
0.5 (p + 9) + 0.15 p + 0.3 (p - 2) = 13.5
0.5 p + 4.5 + 0.15 p + 0.3 p - 0.6 = 13.5
0.95 p = 9.6
p = 10
So, number of pineapples = 10
Number of pears = 10 + 9 = 19
Number of kiwis = 10 - 2 = 8
1 hour = 50 km
3 hours = 50 x 3 = 150 km
Answer: The car would go for 150 km in 3 hours.
Answer:
Quadratic equation follows form: ax^2 + bx + c = 0
a = 8
b = - 6
c = 13
