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lianna [129]
3 years ago
5

Find the zeros of the polynomial function f(x)=x^3-2x^2-8x

Mathematics
2 answers:
kotegsom [21]3 years ago
6 0
The roots are x=0,4,-2
KengaRu [80]3 years ago
5 0
First factor out that x
f(x)=x(x^2-2x-8)
what 2 numbers multiply to get -8 and add to get -2?
-4 and 2
f(x)=(x-0)(x-4)(x+2)
set to zero
x-0=0
x=0

x-4=0
x=4

x+2=0
x=-2

the zeroes are at x=-2,0 and 4
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Answer:

Step-by-step explanation:

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Margin of error = z√[p1(1 - p1)/n1 + p2(1 - p2)/n2]

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α = 1 - 0.95 = 0.05

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3 0
3 years ago
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Step-by-step explanation:

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what is the width of a rectangle with a length of 6/7 feet and an area of 5 square feet. What is the width of the rectangle
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Vikentia [17]

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