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3 years ago

Find the zeros of the polynomial function f(x)=x^3-2x^2-8x

Mathematics

2 answers:

kotegsom [21]3 years ago

6 0

The roots are x=0,4,-2

KengaRu [80]3 years ago

5 0

First factor out that x
f(x)=x(x^2-2x-8)
what 2 numbers multiply to get -8 and add to get -2?
-4 and 2
f(x)=(x-0)(x-4)(x+2)
set to zero
x-0=0
x=0

x-4=0
x=4

x+2=0
x=-2

the zeroes are at x=-2,0 and 4

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ArbitrLikvidat [17]

Answer:

669.9 ft³

Step-by-step explanation:

The formula for volume of a cone:

$v=\pi r^2*\frac{h}{3} (3.14*radius*radius*\frac{height}{3} )$

$r = radius,\pi =pi,h=height.$

The radius is 8; the height is 10.

From here, we can just plug the numbers into the formula.

$\pi 8^2*\frac{10}{3} (3.14*8*8*\frac{10}{3} ) = 669.866666667.$

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3 years ago

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Gwar [14]

Answer:

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Step-by-step explanation:

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3 years ago

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In the circle shown below, ∠BAC is a central angle, r is the length of AB, and θ is the measure of ∠BAC in degrees.

Ket [755]

Answer:

Option 4 is the right answer.

Step-by-step explanation:

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3 years ago

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liq [111]

Answer:

Step-by-step explanation:

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Sav [38]

$\displaystyle\int_8^{10}(x-8)(x-9)(x-10)\,\mathrm dx$

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$y=x-9\implies\begin{cases}y-1=x-10\\y+1=x-8\\\mathrm dy=\mathrm dx\end{cases}$

so that the integral is equivalent to

$\displaystyle\int_{-1}^1y(y+1)(y-1)\,\mathrm dy$

Notice that

$f(y)=y(y+1)(y-1)\implies f(-y)=-y(-y+1)(-y-1)=-y(y-1)(y+1)=-f(y)$

which means $f(y)$ is odd, so

$\implies\displaystyle\int_{-1}^1f(y)\,\mathrm dy=0$

Perhaps more work than necessary, but it does make it easier to see that the original integrand exhibits some symmetry about $x=9$ .

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