All categories

3 years ago

2:4 14:20 proportion? show work thx

1 answer:

4 0

$2:4=\dfrac{2}{4};\ 14:20=\dfrac{14}{20}\\\\\dfrac{2}{4}=\dfrac{14}{20}\ \ \ \ |cross\ multiply\\\\2\cdot20=4\cdot14\\\\40=56\ \ \ |FALSE$

Answer: It's not proportion.

You might be interested in

What happens to the width of a confidence interval for a population mean if the level of confidence is increased without changin

natulia [17]

Answer: If the level of confidence is increased without changing the sample size then The margin of error will decrease because the critical value will decrease. The decreased margin of error will cause the confidence interval to be narrower.

where;

Margin of error = Critical value × Standard deviation

Here, it can be duly noted that Margin of error has a positive relation with critical value, i.e The margin of error will decrease because the critical value will decrease.

whereas;

The confidence interval is the value ± the margin of error.

Therefore, the decreased margin of error will cause the confidence interval to be narrower.

7 0

3 years ago

Simple interest $1200 8% 2years

Gennadij [26K]

This is a screen shot of an online calculator called mathportal.com it shows the work used to find the answer to this question

Hope this helped and have an amazing day :)

-yO mAmA

5 0

3 years ago

Solve the riddle: “I am thinking of a number that is 60,000 when rounded to the nearest ten, hundred, or thousand. What could th

Virty [35]

The answer would be 59,999.

3 0

3 years ago

PLEASE HELP ASAP 50 POINTS

Katen [24]

Answer:

3x times 5=5 times 3x

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the

zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

$d = \frac{1}{2} ({v-0})t$

$5.5= \frac{1}{2} (1.6v)$

The speed of the sprinter then become:

$v = 6.875 m/s$

Part (b)

Convert the weight of the sprinter to mass:

$m = \frac{w}{g}$

$m = \frac{706}{9.8}$

$m = 72 kg$

KE (Kinetic Energy) can then be calculated as:

$KE = \frac{1}{2} mv^{2}$

$KE = \frac{1}{2} (72)(6.875)^{2}$

$KE = 1701.56 J = 1.70 kJ$

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

$P = \frac{KE}{t} \\\$

$P = \frac{1701.56}{1.6}$

$P = 1063.48 W = 1.06 kW$

5 0

3 years ago