2 years ago

13.50x23 con procedimiento

Mathematics

1 answer:

VashaNatasha [74]2 years ago

4 0

Dowloand mw it help you you can do it there 13.50*23

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Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s

ozzi

Answer:

$10.9\ \text{m/s}^2$

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

$\mu$ = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

$F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2$

La aceleración del bloque es $10.9\ \text{m/s}^2$ .

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2 years ago

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