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AlexFokin [52]
3 years ago
6

Factor completely, x^2+25. A).(X+5)(X+5). B).(X+5)(X-5). C).(X-5)(X-5). D.Prime.

Mathematics
2 answers:
Tatiana [17]3 years ago
4 0
The answer you are looking for is B. If you use the FOIL method (first,outer,inner,last) of multiplication, you will find that (x+5) times (x-5) is actually x^2+25. Hope this helps! Comment if you have questions!!! :)
Katena32 [7]3 years ago
4 0
B.(X+5)(5-x) is the answer to the question
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3 years ago
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3 years ago
Soft drink consumption in New Zealand. A survey commissioned by the Southern Cross Healthcare Group reported that 16% of New Zea
lidiya [134]
<h2>Answer with explanation:</h2>

Given : The proportion of New Zealanders consume five or more servings of soft drinks per week :\hat{p}= 0.16

a) The number of survey respondents reported that they consume five or more servings of soft drinks per week = 2006

b) Confidence interval for population proportion (p) :

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} = Sample proportion.

n= Sample size.

z* = Critical value.

For n= 2006 , \hat{p}= 0.16 and critical value for 95% confidence interval : z* = 1.96

Then , the required confidence interval will be :

0.16\pm (1.96)\sqrt{\dfrac{ 0.16(1- 0.16)}{2006}}

0.16\pm (1.96)\sqrt{ 0.000066999002991}

0.16\pm (1.96)(0.00818529186963)

0.16\pm 0.0160431720645

(0.16-0.0160431720645,\ 0.16+0.0160431720645)

(0.143956827935,\ 0.176043172064)\approx(0.144,\ 0.176)

i.e. A 95% confidence interval for the proportion of New Zealanders who report that they consume five or more servings of soft drinks per week. = (0.144,\ 0.176)

c) (0.144,\ 0.176)=(0.144\times100\%,\ 0.176\times100\%)

=(14.4\%,\ 17.6\%)176\times100\%)[/tex]

d) The estimate might be biased because the survey is taken online that means offline New Zealanders are out of consideration.

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Answer:

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