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4 years ago

MO bisects m A. x = 13, B. x = 13, C. x = 14, D. x = 14,

Mathematics

1 answer:

nadezda [96]4 years ago

8 0

For the given question above, the full question must have read as:
MO bisects m<LMN,<LMO =6x-20 and <NMO 2x+36. Solve for x and find m<LMN. The diagram is not to scale.

If MO bisect the angles, then the 2 resulting angles are equal in size so you will have:
6x - 20 = 2x + 36

Solve:
6x - 20 = 2x + 36

The answer would be: x = 14, <LMN=128

You might be interested in

(7^2)^4= n^8 solve for n

S_A_V [24]

Answer:

n=7

Step-by-step explanation:

(7^2)^4= n^8

We know that a^b^c = a^(b*c)

7^(2*4) = n^8

7^8 = n^8

Since the exponents are the same, the bases must be the same

n=7

4 0

3 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

A certain shade of pink is created by adding 3 cups of red paint to 7 cups of white paint.

vazorg [7]

Answer:

7/3 is constant of proportionality and, 3/7 of a cup of red paint should be added to 1 cup of white paint.

Step-by-step explanation:

Constant of proportionality is the constant value of the ratio of two proportional quantities x and y; usually written y = kx, where k is the factor of proportionality.

To make color pink,

for every 3 cups of red , we need 7 cups of white.

Let 'r' be the cups of red required

let 'w' be the cups of white required

so , as per the question

for 3 r we need = 7 w

r = 7/3 w

so, 7/3 is constant of proportionality and, 3/7 of a cup of red paint should be added to 1 cup of white paint.

You already have the answer! ;)

4 0

3 years ago

Solve 4(x-3) - 2(x - 1) >0. { xl x>-5) {xl x>5] {xl x<-5) {xl x<5}

zloy xaker [14]

Answer:

{xl x > 5)

Hope This Helps!

7 0

3 years ago

c. Using a standard deck of 52 cards, the probability of selecting a 4 of diamonds or a 4 of hearts is an example of a mutually

dybincka [34]

Answer:

True

Step-by-step explanation:

If two events X and Y are mutually exclusive,

Then,

P(X∪Y) = P(X) + P(Y)

Let A represents the event of a diamond card and B represent the event of a heart card,

We know that,

In a deck of 52 cards there are 4 suit ( 13 Club cards, 13 heart cards, 13 diamond cards and 13 Spade cards )

That is, those cards which are heart can not be diamond card,

⇒ A ∩ B = ∅

⇒ P(A∩B) = 0

Since, P(A∪B) = P(A) + P(B) - P(A∩B)

⇒ P(A∪B) = P(A) + P(B)

By the above statement,

Events A and B are mutually exclusive,

Hence, the probability of selecting a 4 of diamonds or a 4 of hearts is an example of a mutually exclusive event is a true statement.

4 0

3 years ago