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WARRIOR [948]
4 years ago
7

MO bisects m A. x = 13, B. x = 13, C. x = 14, D. x = 14,

Mathematics
1 answer:
nadezda [96]4 years ago
8 0
For the given question above, the full question must have read as:
<span>MO bisects m<LMN,<LMO =6x-20 and <NMO 2x+36. Solve for x and find m<LMN.  The diagram is not to scale.
</span>
<span>If MO bisect the angles, then the 2 resulting angles are equal in size so you will have:
6x - 20 = 2x + 36

Solve:
</span>6x - 20 = 2x + 36



The answer would be: x = 14, <LMN=128

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Answer:

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velikii [3]

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4 0
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Read 2 more answers
Please help, I’ll mark your answer as brainliest!
statuscvo [17]

Answer:

(x-230)^2+(y-220)^2=6100

Step-by-step explanation:

The equation for a circle is (x-h)^2+(y-k)^2=r^2, where (h,k) is the vertex of the circle and r is the radius. Immediately, since the center of the circle is given, we know what h and k are. h is 230 and k is 220.

The only thing we need to find is the radius, which will just be the distance from the center (230,220) to a point on the circumference (170,170). The distance between them can be calculated using the <u>distance formula</u>, which is really just the <u>Pythagorean Theorem</u> rearranged. The formula states that d=\sqrt{x^2+y^2}, where x is the change in the x-coordinates of the two points and y is the change in the y-coordinates of the two points. Plug-in x for 60 and y for 50 to get d=\sqrt{50^2+60^2}. Solve for d, arriving at \sqrt{6100}. Therefore, the radius of the circle is \sqrt{6100}.

Finally, we have all of the components to create the equation of the circle. Plug-in 230 for h, 220 for k, and \sqrt{6100} for r.

The equation of the circle will be (x-230)^2+(y-220)^2=6100.

Hope this helps :)

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2 years ago
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Answer:

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3 years ago
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rjkz [21]

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4

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