3 years ago

MO bisects m A. x = 13, B. x = 13, C. x = 14, D. x = 14,

1 answer:

8 0

For the given question above, the full question must have read as:
MO bisects m<LMN,<LMO =6x-20 and <NMO 2x+36. Solve for x and find m<LMN. The diagram is not to scale.

If MO bisect the angles, then the 2 resulting angles are equal in size so you will have:
6x - 20 = 2x + 36

Solve:
6x - 20 = 2x + 36

The answer would be: x = 14, <LMN=128

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P(-3,-5) and Q(1, -3) represent points in a coordinate plane. Find the midpoint of PQ.

Karolina [17]

Step by step explanation :

The two points are ,

P( -3 , -5)
Q (1 , -3)

We can find the midpoint by finding the median of x coordinate and y coordinate .

$\tt\to Midpoint = \bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\tt\to Midpoint =\bigg(\dfrac{-3+1}{2},\dfrac{-5-3}{2}\bigg)\\\\\tt\to Midpoint = \bigg( \dfrac{-2}{2},\dfrac{-8}{2}\bigg) \\\\\sf\to\boxed{\orange{\tt Midpoint = (-1,-4)}}$