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notsponge [240]
2 years ago
13

You and your dog are walking along a pond. Your dog looks into the still water and is startled to see its reflection. Which phen

omenon is
responsible for the appearance of the dog's reflection on the water's surface?
А. diffraction of water waves
B. reflection of lightwaves
C. refraction of lightwaves
D. reflection of water waves
E. refraction of water waves
Physics
1 answer:
padilas [110]2 years ago
8 0

Answer: B

Explanation: light allows you to see, when light reflects off the water in a certain way it has a mirroring effect. refraction changes how things are seen based on the medium light is in, so this question is not about that.

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A competitive go-cart driver is traveling at a speed of 32m/s. He sees a caution flag go up and slows down at a rate of -1.5 m/s
djyliett [7]

Answer:

His final velocity is 15.8 m/s.

Step-by-step explanation:

Given:

Initial velocity of the driver is, u=32 m/s

Acceleration of the driver is, a=-1.5 m/s²

Time taken to reach final velocity is, t=10.8 s.

The final velocity is given using the Newton's equations of motion as:

v=u+at, where, v is the final velocity.

Now, plug in the given values and solve for v.

v=32-1.5(10.8)\\v=32-16.2=15.8\textrm{ m/s}

Therefore, his final velocity is 15.8 m/s.

5 0
2 years ago
A tennis player standing 12.6m from the net hits the ball at 3.00 degrees above the horizontal. To clear the net, the ball must
mezya [45]
We actually don't need to know how far he/she is standing from the net, as we know that the ball reaches its maximum height (vertex) at the net. At the vertex, it's vertical velocity is 0, since it has stopped moving up and is about to come back down, and its displacement is 0.33m. So we use v² = u² + 2as (neat trick I discovered just then for typing the squared sign: hold down alt and type 0178 on ur numpad wtih numlock on!!!) ANYWAY....... We apply v² = u² + 2as in the y direction only. Ignore x direction. 
IN Y DIRECTION: v² = u² + 2as 0 = u² - 2gh u = √(2gh) (Sub in values at the very end) 
So that will be the velocity in the y direction only. But we're given the angle at which the ball is hit (3° to the horizontal). So to find the velocity (sum of the velocity in x and y direction on impact) we can use: sin 3° = opposite/hypotenuse = (velocity in y direction only) / (velocity) So rearranging, velocity = (velocity in y direction only) / sin 3° = √(2gh)/sin 3° = (√(2 x 9.8 x 0.33)) / sin 3° = 49 m/s at 3° to the horizontal (2 sig figs)
4 0
3 years ago
Read 2 more answers
The steps in the heating of a metal seat in a park are listed below: Step 1: Heat travels from the sun to Earth Step 2: Heat tra
I am Lyosha [343]

The steps in the heating of a metal seat in a park are:

Step 1: Heat travels from the sun to Earth

Step 2: Heat travels through atmosphere to the top of the seat

Step 3: Heat from the top of the seat travels through the seat to the lower parts of the seat.

-- Heat is transferred by radiation in Step 1 and Step 2. <em>(B)</em>

-- From the top of the seat to the bottom, heat is transferred by conduction.  

There's no convection happening anywhere in the park-hot-seat scenario.

3 0
2 years ago
Read 2 more answers
hooke's law is described mathematically using the formula fsp=-kx. which statement is correct about spring force, fsp? A. It is
bogdanovich [222]

Answer:

A. It is always a positive force

Explanation:

Hooke's law describes the relation between an applied force and extension ability of an elastic material. The law states that provided the elastic limit, e, of a material is not exceeded, the force, F, applied is proportional to the extension, x, provided temperature is constant.

i.e F = - kx

where k is the constant of proportionality, and the minus sign implies that the force is a restoring force.

The applied force can either be compressing or stretching force.

6 0
3 years ago
Can someone help me?​
Leviafan [203]

Car X traveled 3d distance in t time.  Car Y traveled 2d distance in t time. Therefore, the speed of car X, is 3d/t,  the speed of car Y, is 2d/t. Since speed is the distance taken in a given time.

In figure-2, they are at the same place, we are asked to find car Y's position when car X is at line-A. We can calculate the time car X needs to travel to there. Let's say that car X reaches line-A in t' time.

V_x .t' = 3d\\ \frac{3d}{t} .t' = 3d\\ t'=t

Okay, it takes t time for car X to reach line-A. Let's see how far does car Y goes.

V_y.t = \frac{2d}{t} .t = 2d

We found that car Y travels 2d distance. So, when car X reaches line-A, car Y is just a d distance behind car X.

4 0
2 years ago
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