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Tju [1.3M]
3 years ago
8

80

Physics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

1 million hahahahahahahahhahah

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Which events took place during the Copernican revolution, when most people started to believe in a heliocentric model of the sol
balu736 [363]
<h2>2) Copernicus rediscovered Aristarchus’s heliocentric model.</h2>

Before Copernican Revolution, people did believe in the ptolemain model that establishes the description of the Universe with the earth at the center having sun, moon, starts and planets all orbited earth. On the other hand, the heliocentric model establishes the sun at the center of the solar system and this starts with the publication of Nicolas Copernicus named <em>De revolutionibus orbium coelestium.</em>

<h2>5) Newton’s theories of gravity increased understanding of the movement of planets.</h2>

The revolution ended with Isaac Newton's work over a century later. As you well know, Newton was both a physicist and mathematician, better known for his prodigal work called <em>Philosophiæ Naturalis Principia Mathematica. </em>In this revolution, he is known for his laws of motion and universal gravitation increasing understanding of the movement of planets.

7 0
3 years ago
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What three structures to the bodies of all vascular plants have?? HELP!!!!
bearhunter [10]
All vascular plants have parenchyma, collenchym<span>Vascular tissue transports food, water, hormones and minerals within the plant. Vascular tissue includes </span>xylem<span>, </span>phloem<span>, parenchyma, and cambium cells.</span>a, and sclerenchyma cells. Hoped it help!
3 0
3 years ago
Interactive Solution 9.37 presents a method for modeling this problem. Multiple-Concept Example 10 offers useful background for
viva [34]

Answer:

21.67 rad/s²

208.36538 N

Explanation:

\omega_f = Final angular velocity = \dfrac{1}{6}78=13\ rad/s

\omega_i = Initial angular velocity = 78 rad/s

\alpha = Angular acceleration

\theta = Angle of rotation

t = Time taken

r = Radius = 0.13

I = Moment of inertia = 1.25 kgm²

From equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{13-78}{3}\\\Rightarrow \alpha=-21.67\ rad/s^2

The magnitude of the angular deceleration of the cylinder is 21.67 rad/s²

Torque is given by

\tau=I\alpha\\\Rightarrow \tau=1.25\times -21.67\\\Rightarrow \tau=-27.0875

Frictional force is given by

F=\dfrac{\tau}{r}\\\Rightarrow F=\dfrac{-27.0875}{0.13}\\\Rightarrow F=-208.36538\ N

The magnitude of the force of friction applied by the brake shoe is 208.36538 N

5 0
3 years ago
A child bounces a 48 g superball on the sidewalk. the velocity change of the superball is from 26 m/s downward to 17 m/s upward.
Nataly_w [17]
By definition we have the momentum is:
 P = m * v
 Where,
 m = mass
 v = speed
 Before the impact:
 P1 = (0.048) * (26) = 1.248 kg * m / s
 After the impact:
 P2 = (0.048) * (- 17) = -0.816 Kg * m / s.
 Then we have that deltaP is:
 deltaP = P2-P1
 deltaP = (- 0.816) - (1,248)
 deltaP = -2,064 kg * m / s.
 Then, by definition:
 deltaP = F * delta t
 Clearing F:
 F = (deltaP) / (delta t)
 Substituting the values
 F = (- 2.064) / (1/800) = - 1651.2N
 answer:
 the magnitude of the average force exerted on the superball by the sidewalk is 1651.2N
3 0
4 years ago
You grab the handle of the door in the picture, and pull as hard as you can. Unfortunately, this door should
chubhunter [2.5K]

Answer:

Explanation:

The solved solution is on the attach document

8 0
3 years ago
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