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Alenkinab [10]
3 years ago
7

A man does 4,780 J of work in the process of pushing his 2.70 103 kg truck from rest to a speed of v, over a distance of 25.5 m.

Neglecting friction between truck and road, determine the following. (a) the speed v (in m/s) 1.88 Correct: Your answer is correct. m/s (b) the horizontal force exerted on the truck (in N) N
Physics
1 answer:
wolverine [178]3 years ago
4 0

Answer:

(A) Velocity will be 1.88 m/sec

(b) Force will be 187.45 N

Explanation:

We have given work done = 4780 j

Distance d = 25.5 m

(A) Mass of the truck m = m=2.70\times 10^3kg

We know that kinetic energy is given  by

KE=\frac{1}{2}mv^2

So v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2\times 4780}{2.7\times 10^3}}=1.88m/sec

(B) We know that work done is given by

W = Fd

So F=\frac{W}{d}=\frac{4780}{25.5}=187.45N

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dedylja [7]

Answer:

1) 9.8×10⁻⁹ m/s

2) 50970.3238656 L

Explanation:

1) In 30 days hair grows 1 inch

1 inch = 2.54 cm

1 cm = 0.01 m

2.54 cm = 2.54 × 0.01 m

⇒2.54 cm = 0.0254 m

30 days = 30×24×60×60 = 2592000 seconds

Speed = Distance / Time

\text{Speed}=\frac{0.0254}{2592000}=9.8\times 10^{-9}\ m/s

Speed at which hair grows is 9.8×10⁻⁹ m/s

2) 1 ft = 0.3048 m

0.3048 m = 30.48 cm

1 ft = 30.48 cm

15 ft = 15×30.48 = 457.2 cm

8 ft = 8×30.48 = 243.84 cm

Volume of water in pool = Length × Width × Depth

⇒Volume of water in pool = 457.2×457.2×243.84

⇒Volume of water in pool = 50970323.8656 cm³

or

Volume of water in pool = 15×15×8 = 1800 ft³

1 ft³ = 30.48³ cm³

1800 ft³ = 30.48³ × 1800 = 50970323.8656 cm³

Converting to liters

1 L = 1000 cm³

0.001 L = 1 cm³

50970323.8656 cm³ = 50970323.8656×0.001 = 50970.3238656 L

Volume of water in pool is 50970.3238656 L

6 0
3 years ago
Which of the following is the most reasonable weight in units of newtons for an average adult?
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Answer: The reason weight for average adult is 530N

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530=m×9.8

g is a constant of 9.8m/s2

We divide both sides by 9.8 to get

54kg then this weight is reasonable for an average adult.

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A 4-kg object is moving with a speed of 5 m/s at a height of 2 m. The kinetic
tatyana61 [14]

Hello!

\large\boxed{KE = 50J}

Use the formula for kinetic energy:

KE = \frac{1}{2}mv^{2}

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KE = \frac{1}{2} (4)5^{2}

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7 0
3 years ago
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