Answer the photo below thanks

4. k/6 = 8/16 5. 5.4/7 = 27/h 6. 8/11 = 4/y+2

kupik [55]

Answer:

4. $k=3\\$

5. $h=35$

6. $\frac{7}{2}$ or 3.5

Step-by-step explanation:

$\frac{k}{6}=\frac{8}{16}$

Multiply those 2 values whose diagonal has both terms and divide by the term whose diagonal has the variable.

$k=\frac{8*6}{16}\\ k=\frac{48}{16}\\ k=3$

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$\frac{5.4}{7}=\frac{27}{h}$

$h=\frac{7*27}{5.4} \\h=\frac{189}{5.4}\\ h=35$

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$\frac{8}{11}=\frac{4}{y+2}$

$y+2=\frac{11*4}{8}\\ y=\frac{11*4}{8}-2\\y=\frac{44}{8}-2 \\y=\frac{11}{2}-2\\ y=\frac{11-2*2}{2}\\ y=\frac{11-4}{2}\\ y=\frac{7}{2}=3.5$

7 0

2 years ago

PLS HELP will give brainliest answer both

wariber [46]

Answer:

8 3/5

false

Step-by-step explanation:

4 0

2 years ago

Two geometrically similar jugs have volumes of 1000 cm3and 512 cm3.They have circular bases. The diameter of the base of the lar

Aleks [24]

Complete Question

Two geometrically similar jugs have volumes of 1000 cm³and 512 cm³.They have circular bases. The diameter of the base of the larger jug is 9 cm.

Calculate the diameter of the smaller jug.

Answer:

7.2 cm

Step-by-step explanation:

To solve the above question,we have the proportion

Smaller volume/ Larger volume = (Smaller diameter/ Larger diameter)³

We are to find the smaller diameter

Hence our formula is give as

Cube root(Smaller volume/ Larger volume)= Smaller diameter/ Larger diameter

=cube root( 512/1000) = x/9

= 8/10 = x/9

Cross Multiply

10x = 8 × 9

10x = 72

x = 72/10

x = 7.2cm

Therefore, the diameter of the second jug is 7.2 cm

3 0

3 years ago

Please help i will igve brainliest

adelina 88 [10]

3. you cannot simplify √30

4 0

2 years ago

Help me with these questions

Elena L [17]

Answer: a = 4, b = 163,422

Step-by-step explanation:

$P = P_{0} e^{kt}$ P is the new population, P₀ is the initial population, k is the growth rate, t is the time elapsed.

Part a) What do we know?

P = 7003

P₀ = unknown

k = .21 (converted 21% into a decimal)

t = 36 yrs (2006 - 1970)

$P = P_{0} e^{kt}$ need to solve for P₀

$7003 = P_{0} e^{(.21)(36)}$

$7003 = P_{0} e^{7.56}$

7003 = P₀ (1920)

$\frac{7003}{1920} = P_{0}$

3.6 = P₀

rounded to the nearest whole number = 4

Part b) What do we know?

P = unknown

P₀ = 7003

k = .21 (converted 21% into a decimal)

t = 15 yrs (2021 - 2006)

$P = P_{0} e^{kt}$ need to solve for P₀

$P = 7003 e^{(.21)(15)}$

$P = 7003 e^{3.15}$

P = 7003(23.33)

P = 163,422.46

rounded to the nearest whole number = 163,422

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Answer: 2, -1

Step-by-step explanation:

eˣ² = eˣ * e²

eˣ² = eˣ⁺²

x² = x + 2

x² - x - 2 = 0

(x - 2)(x + 1) = 0

x - 2 = 0 or x + 1 = 0

x = 2 or x = -1

Check both answer for validity:

eˣ² = eˣ⁺²

e⁴ = e⁴ or e¹ = e¹

TRUE TRUE

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Answer: 0 = ln 1

Step-by-step explanation:

$e^{-10} = \frac{1}{e^{10}}$

$ln(e^{-10}) = ln(\frac{1}{e^{10}})$

-10 = ln 1 - 10 log rules say division is subtraction

0 = ln 1

5 0

2 years ago