Answer:
C.) A new compound is formed - salt
Explanation:
Na is a metal
Cl is a nonmetal
When they are combined, they form ionic bonds as they seek to fill their octets. Salts are ionic compounds.
Answer:
In fluorine, the electrons are tightly held to the nuclei. The electrons have little chance to wander to one side of the molecule, so the London dispersion forces are relatively weak. At a low enough temperature the molecules will all be solids. At a high enough temperature they will all be gases.
Explanation:
Answer:
-162,5 kJ/mol
Explanation:
Cl(g) + 2O2(g) --> ClO(g) + O3(g) ΔH = 122.8 kJ/mol (as we used the reaction in the opposite direction, it will turn the enthalpy from exothermic to endothermic)
2O3(g) --> 3O2(g) ΔH = -285.3 kJ/mol
Cl(g) + O2(g) --> ClO(g) + O3(g) ΔH = 122.8 kJ
+ 2O3 (g) --> 3O2(g) ΔH = - 285.3 kJ
O3(g) + Cl(g) --> ClO(g) + 2O2(g) ΔH = 122.8 + (-285.3) = -162,5 kJ
Answer:
% yield = 62.21 %
Explanation:
- C2H4(g) + H2O(l) → C2H6O(l)
∴ mass C2H4(g) = 4.6 g
∴ mass C2H6O(l) = 4.7 g
- % yield = ((real yield)/(theoretical yield))×100
theretical yield:
∴ molar mass C2H4(g) = 28.05 g/mol
⇒ mol C2H4(g) = (4.6 g)*(mol/28.05 g) = 0.164 mol
⇒ mol C2H6O(l) = (0.164 mol C2H4)*(mol C2H6O(l)/molC2H4(g))
⇒ mol C2H6O(l) = 0.164 mol
∴ molar mass C2H6O(l) = 46.07 g/mol
⇒ mass C2H6O(l) = (0.164 mol)*(46.07 g/mol) = 7.55 g
⇒ theoretical yield = 7.55 g
⇒ % yield = (4.7 g)/(7.55 g))*100
⇒ % yield = 62.21 %
