Question

A 50 gram object with a specific heat of 0.3825 J/g*C releases 4593 joules of heat.

Answer 1

Answer:

475.26°C

Explanation:

Given parameters:

Mass of object = 50g

Specific heat  = 0.3825J/g°C

Quantity of heat  = 4593Joules

Initial temperature  = 235.16°C

Unknown:

Final temperature = ?

Solution:

The quantity of heat absorbed by a body is a function of the mass, specific heat capacity and temperature change the body undergoes.

Mathematically, this relationship is given as;

              H  = m c Ф

where H is the quantity of heat

           m is the mass of the body

            c is the specific heat capacity

            Ф is the temperature difference

Ф  = final temperature - initial temperature

  Since we are solving for final temperature, let us substitute for other given parameters;

    H  =  m c ( final temperature - initial temperature)

       4593  = 50 x 0.3825 x (F  - 235.16)

       F - 235.16  = 240.1

             F  = 240.1 + 235.16 = 475.26°C