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4 years ago

Please help me with this

Mathematics

1 answer:

juin [17]4 years ago

7 0

Answer:

The radius of the cylinder is $r=6$ meters.

Step-by-step explanation:

To determine:

What is radius?

Information Fetching and Solution Steps:

The volume of the cylinder = 1,921.68 cubic meters

$\pi \approx 3.14$

The height = 17 m

As the formula of the volume of the cylinder

$V=\:\pi \:r^{2} \:h$

The radius can be determine as

$r^{2} \:=\:\frac{V}{\pi \:h}$

$r=\sqrt{\frac{V}{\pi \:\:h}}$

$\:r=\sqrt{\frac{1921.68}{\left(3.14\right)\:\left(17\right)}}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$r=\sqrt{\frac{1921.68}{3.14\cdot \:17}}$

$\mathrm{Multiply\:the\:numbers:}\:3.14\cdot \:17=53.38$

$r=6$ meters

Therefore, the radius of the cylinder is $r=6$ meters.

Keywords: radius of the cylinder, volume of cylinder

Learn more about volume of cylinder from brainly.com/question/1027712

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Answer:

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Step-by-step explanation:

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Find all solutions in the interval from [0,2pi)<br> 2cos(3x)= -sqrt{2}

algol [13]

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<u>Step-by-step explanation:</u>

Find all solutions in the interval from [0,2pi)

$2cos(3x)= -\sqrt{2}$

⇒ $2cos(3x)= -\sqrt{2}$

⇒ $\frac{2cos(3x)}{2}= \frac{-\sqrt{2}}{2}$

⇒ $cos3x= \frac{-\sqrt{2}(\sqrt{2})}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-2}{2{\sqrt{2}}}$

⇒ $cos3x= \frac{-1}{{\sqrt{2}}}$

⇒ $cos^{-1}(cos3x)= cos^{-1}(\frac{-1}{{\sqrt{2}}})$

⇒ $3x=\pm \frac{\pi}{4}$

⇒ $x=\pm \frac{\pi}{12}$

Cosine General solution is :

$x = \pm cos^{-1}(y)+ 2k\pi$

⇒ $x = \pm \frac{\pi}{12}+ 2k\pi$ , k is any integer .

At k=0,

⇒ $x =\frac{\pi}{12}$ ,

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⇒ $x = - \frac{\pi}{12}+ 2\pi$

⇒ $x = \frac{23\pi}{12}$

Therefore , Solutions of $2cos(3x)= -\sqrt{2}$ in the interval from [0,2pi) is $x =\frac{\pi}{12}$ and $x = \frac{23\pi}{12}$ .

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saveliy_v [14]

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