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daser333 [38]
3 years ago
7

Please solve the following quadratic equation and show your work: x^2 -x =30

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0
Rewriting the equation as a quadratic equation equal to zero:
     x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
     (x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
     x + 5 = 0  => x = -5
     x - 6 = 0  => x = 6
Therefore, our solutions are x = -5 and x = 6.
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3 years ago
Can someone please give me the answers to this? ... please ...
Gelneren [198K]

Step-by-step explanation:

the midpoint between 2 points (x1, y1) and (x2, y2) is simply ((x1+x2)/2, (y1+y2)/2).

so,

1.

(9, 7) to (4, -3)

midpoint is ((9+4)/2, (7+ -3)/2) = (13/2, 4/2) = (6.5, 2)

2.

(-7, -5) to (2, 1)

midpoint is ((-7+2)/2, (-5+1)/2) = (-5/2, -4/2) = (-2.5, -2)

3.

now we have the midpoint and need the second point.

(4, 2) over (3, 4) to (x, y)

3 = (4 + x)/2

6 = 4 + x

x = 2

4 = (2 + y)/2

8 = 2 + y

y = 6

4.

(-2, 1) over (-3, 2) to (x, y)

-3 = (-2 + x)/2

-6 = -2 + x

x = -4

2 = (1 + y)/2

4 = 1 + y

y = 3

5 0
2 years ago
Round 222,977 to the nearest hundred
Fittoniya [83]
223,000 is the answer
7 0
3 years ago
Read 2 more answers
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