First you have to make all the fractions have a common denominator to add them so since 3/16 is the largest denominator you have to convert the others to have the denominator of 16. 1/8 = 2/16. 1/4 = 4/16. so if you add the numerators that’s 3 + 2 + 4 = 9. so the answer would be 9/16, and this cannot be simplified so it is your final answer:)
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
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