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nadya68 [22]
3 years ago
8

Write an equation that can be used to answer each question

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

1. (70 - 44) / 2

2. (45.00 - 25.50) / 6

3. (75 - 39) / 3

4. (90 - 30 +10) / 3

5. (100- 30+10) / 10

6. (50 - 5) / 10


PS: / means divide or division. also remember PEMDAS


Hope this helped you (;      

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File Is Attached To The Question
Paul [167]

Answer:

<h2>3.05x(output for x)</h2><h2>39.65</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • function
  • PEMDAS
<h3>let's solve:</h3>

according to the question

the function is

f(x)=3.05x(first answer)

let's justify

f(1)=3.05×1

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LIKEWISE

f(3)=3.05×3

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therefore

it is the function

answer for the second question

f(13)=3.05×13

=39.65

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3 years ago
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2/4

Step-by-step explanation:

Change the 2 1/2 to 2 2/4

now subtract 1/4 from 2 2/4 leaving 2 1/4

Now subtract 1 3/4 from 2 1/4 in which you get 2/4

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7 0
2 years ago
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Mama L [17]

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Step-by-step explanation:

7 0
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how much antifreeze 25% antifreeze and 50% antifreeze should be combined to give 40 gallon of 30% antifreeze?​
VARVARA [1.3K]

32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Solution:</u></h3>

From given,

Final mixture is 40 gallon

Let "x" be the gallon of 25 % antifreeze

Then, (40 - x) is the gallon of 50 % antifreeze

Therefore, according to question,

"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3><u>Therefore, we frame a equation as:</u></h3>

25 % of x + 50 % of (40 - x) = 30 % of 40

Solve for "x"

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Thus, 32 gallons of 25 % antifreeze is used

Then, (40 - x) = (40 - 32) = 8

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Answer:

B and D

Step-by-step explanation:

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