All categories

3 years ago

This year, Faaria's car is worth 22,000. If the value of Faaria's car decreases by 8%, what will her car be worth next year?

Mathematics

1 answer:

Grace [21]3 years ago

5 0

Your answer would be 20,240$ because 22,000 multiplied by .92 = the number fist stated

You might be interested in

Mr. Berkholz wants to invest $5000 into an account to save for his daughter for college. He is 'guaranteed' a 5.2% annual return

Feliz [49]

The answer is: $9,186.69

8 0

3 years ago

Reflect the triangle (-2,-2) (-6,-8) (-8,-8) over the x-axis. What are the new vertices?

Inessa [10]

Reflecting across the x axis changes the y value to the opposite, but doesn't change the x value, so the new values are:
(-2,2), (-6, 8), (-8, 8)

5 0

3 years ago

How do you factor the coefficient of 3/8d+3/4?

nevsk [136]

Actually you have 2 coefficients here: 3/8 and 3/4.

(3/8)d + (3/4) is the same as (3/8)d + (2)(3/8), so this can be factored into

(3/8) [ d + 2 ]

6 0

3 years ago

I need help with this question

Murrr4er [49]

The number of cows is given by

$14\cdot 2^{\frac{y}{5}}$

So, after $k$ years, the number of cows will be

$14\cdot 2^{\frac{y+k}{5}}$

We want this number to be twice as much as the original:

$14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})$

First of all, we can cancel 14 from both sides:

$2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}$

Finally, on the right hand side, we can use the exponent rule

$a^b\cdot a^c=a^{b+c}$

to get

$2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}$

To solve this equation, we must impose that the two exponents are the same:

$\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}$

And clearly this is true if and only if $k=5$ . So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0

3 years ago

(8x2 + 5x – 9) - (3x2 – 5x + 1) = ?

Svetach [21]

Answer:

10x

Step-by-step explanation:

7 0

3 years ago