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earnstyle [38]
3 years ago
15

Your town gets between 8 and 12 inches of snow each month from December to February. Estimate how much snow your town should get

over the entire 3 months from December to February
Mathematics
2 answers:
maksim [4K]3 years ago
5 0
24-36 inches of snow
yulyashka [42]3 years ago
4 0
You would get about 24-26 inches of snow for the entire 3 months.
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faust18 [17]
It’s f(0)=3 because f(0) just means y intercept which is 3
7 0
3 years ago
What is 212% in a decimal
4vir4ik [10]
The answer is:

212/100

=(200/100)+(12/100)

=2.00+0.12

=2.12
7 0
3 years ago
Read 2 more answers
The line represented by the equation y=-3/2x is translated up 3 units.
kati45 [8]

Answer:

(0, 3)

Step-by-step explanation:

     In slope intercept form, the y-intercept is the "b" or, in an example:

           y = mx + b

     - m is the slope

     - b is the y-intercept

     In our first equation, the b is 0 (y=-3/2x, there is no +/- b, so it is 0). If we add positive 3 (up 3 units) then the y-intercept will be 3. This, in a point, is shown with (0, 3) because the y-intercept is where the line hits the y-axis when x is 0.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0
2 years ago
Flying against the wind, an airplane travels 7520 kilometers in 8 hours. Flying with the wind, the same plane travels 6500 kilom
bezimeni [28]

Answer:

Rate of plane in still air = 1120 km/h

Rate of wind = 180 km/h

Step-by-step explanation:

Let the rate (speed) of the plane in still air = u km/h

Let the rate (speed) of the wind = v km/h

Formula for speed is:

Speed = \dfrac{Distance}{Time}

Given that against the wind, airplane travels 7520 km in 8 hours.

The speed against the wind will be slower so,

Against the wind, speed = (u -v ) km/h

Using above formula:

(u-v) = \dfrac{7520}{8} km/h\\(u-v) = 940 km/h ..... (1)

Given that with the wind, airplane travels 6500 km in 5 hours.

The speed with the wind will be faster so,

With the wind, speed = (u +v ) km/h

Using above formula:

(u+v) = \dfrac{6520}{5} km/h\\(u+v) = 1300 km/h ..... (2)

Adding (1) and (2) to solve for u and v:

2u = 2240\\\Rightarrow u = 1120\ km/h

Putting u in (1):

1120-u=940\\\Rightarrow u = 180\ km/h

So, the answers are:

<em>Rate of plane in still air = 1120 km/h</em>

<em>Rate of wind = 180 km/h</em>

<em></em>

6 0
2 years ago
The missing exponent for 1/169?
enot [183]
The missing exponent of 1/169=(1/13)
5 0
3 years ago
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