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Step2247 [10]
3 years ago
10

Simplify the expression. 2(x−2)+5x

Mathematics
2 answers:
LenaWriter [7]3 years ago
6 0
Question: 2x - 4 + 5x
Simplified: 7x - 4
Ber [7]3 years ago
5 0
2(x-2)+5 2x-4+5x 2x+5x=7x 7x-4 7x/7 -4/7 x=-0.571428571
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Would anyone know how to do this
butalik [34]
Your answer will be 5xplus10
8 0
3 years ago
Please explain as well 3x+5y=21 4x-2y=-244x−2y=−24
hodyreva [135]

Step-by-step explanation:

3x + 5y = 21 * (-4) •••••• -12x -20y = -84 (a)

4x - 2y = -24 * (3) •••••• 12x -6y = -72 (b)

(a) + (b)

-26y = -156

y = 6

3x + 5 * 6 = 21

3x = 21 - 30

3x = -9

x = -3

3 0
3 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
Simplify the expression: 4(2x-7) *<br> 6x-7<br> 08x-7<br> 0 2x-28<br> 8x-28
oksian1 [2.3K]

Answer:

Answer is (d)

Step-by-step explanation:

4(2x - 7)

8x - 28

3 0
3 years ago
Read 2 more answers
Solve for x<br> -3(x + 4) - 2 = -2(x - 5)<br> x= -4<br> x = -11/5<br> x = 24<br> x = -24
Gala2k [10]

Answer:

-24

Step-by-step explanation:

-3 (x + 4) - 2 = -2 (x - 5)

-3x - 12 - 2 = -2x + 10

-3x + 2x = 10 + 12 + 2

-x = 24

x = -24

5 0
3 years ago
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