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Alekssandra [29.7K]
2 years ago
15

Question 6(Multiple Choice Worth 1 points)

Mathematics
1 answer:
Dafna11 [192]2 years ago
3 0

Answer:

O The value of f(2) is smaller than the value of f(1).

Step-by-step explanation:

First, let's solve for both. When the problem says f(1) or f(2), this just means that the x value is equal to that. So:
f(1) = -5(1)^2 + 2(1) + 9 = 6
f(2) = -5(2)^2 + 2(2) + 9 = -7
Since f(1) = 6 and f(2) = -7, we know that f(1) is greater than f(2). Therefore, the value of f(2) is smaller than the value of f(1)

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Given $dc = 7$, $cb = 8$, $ab = \frac{1}{4}ad$, and $ed = \frac{4}{5}ad$, find $fc$. Express your answer as a decimal.
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A ↔ B ↔ C ↔ D ↔ E ↔ F

 \frac{1}{4} AD      8      7      \frac{4}{5} AD   ???

AB + BC + CD = AD   <em>segment addition postulate</em>

\frac{1}{4} AD   +   8   +   7   = AD

\frac{1}{4} AD   +       15        = AD

AD         + 60    = 4AD

                  60    = 3AD

                  20    = AD

AB =  \frac{1}{4} AD    =  \frac{1}{4}(20)    = 5

DE =  \frac{4}{5}AD   =  \frac{4}{5}(5)    = 4

CD + DE + EF = CF   <em>segment addition postulate</em>

7   +   4   + EF  = CF

     11        + EF  = CF

Answer: 11 + EF

Note: You did not provide any info about EF.  If you have additional information that you did not type in, calculate EF and add it to 11 to find the length of CF.

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