You HAVE to use Pemdas.
2[3(4^2+1)]-2^3
2(3(16+1))-2^3
2(3(17))-2^3
2*51-2^3
102-8
94.
Explanation: you use Pemdas P-parenthesis
E-exponents
M-multiplication
D-division
A-addition
S-subtraction
Answer:
I think its 4 because all the other ones are adding half of the original number
16-24 adds 8
8-12 adds 4
1-1.5 adds .5
so if it's going to 6 it should be 4 adding 2
6 ! = 720
the definition of n ! ( n factorial ) is
n ! = n(n - 1)(n - 2) ..........× 3 × 2 × 1
6 ! = 6 × 5 × 4 × 3 × 2 × 1 = 720
Answer:
45Y + 13Y equals 58Y is the answer
1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
