Question

Use laws of exponents to simplify inside the parentheses of the given expression ((a ^ - 2 * b ^ 2)/(a ^ 2 * b ^ - 1)) ^ - 3

Answer 1

Answer:

its d

Step-by-step explanation:

ur welcome

Answer 2

Answer:

Step-by-step explanation:

$[\frac{(a^{-2}*b^{2})}{(a^{2}*b^{-1})}]^{-3}=(a^{-2-2}*b^{2+1})^{-3}\\\\\\=(a^{-4}*b^{3})^{-3}=(a^{-4})^{-3}*(b^{3})^{-3}\\\\=a^{-4*-3}*b^{3*-3}=a^{12}*b^{-9}\\\\=\frac{a^{12}}{b^{9}}$

Hint:  $a^{-m}=\frac{1}{a^{m}}\\\\a^{m}*a^{n}=a^{m+n}\\\\(a^{m})^{n}=a^{mn}$