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vazorg [7]
3 years ago
12

Use laws of exponents to simplify inside the parentheses of the given expression ((a ^ - 2 * b ^ 2)/(a ^ 2 * b ^ - 1)) ^ - 3

Mathematics
2 answers:
Vinvika [58]3 years ago
8 0

Answer:

its d

Step-by-step explanation:

ur welcome

Fudgin [204]3 years ago
4 0

Answer:

Step-by-step explanation:

[\frac{(a^{-2}*b^{2})}{(a^{2}*b^{-1})}]^{-3}=(a^{-2-2}*b^{2+1})^{-3}\\\\\\=(a^{-4}*b^{3})^{-3}=(a^{-4})^{-3}*(b^{3})^{-3}\\\\=a^{-4*-3}*b^{3*-3}=a^{12}*b^{-9}\\\\=\frac{a^{12}}{b^{9}}

Hint:  a^{-m}=\frac{1}{a^{m}}\\\\a^{m}*a^{n}=a^{m+n}\\\\(a^{m})^{n}=a^{mn}\\

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A number less than twenty five
padilas [110]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

=(2x^2+2x-3)+(-x+3)

Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

4 0
3 years ago
Find an expression which represents the difference when (3x + 1) is subtracted
NARA [144]

Answer:

-12x

Step-by-step explanation:

(-9x+1) - (3x+1)

-9x + 1 - 3x - 1

-12x

4 0
2 years ago
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