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3 years ago

Use laws of exponents to simplify inside the parentheses of the given expression ((a ^ - 2 * b ^ 2)/(a ^ 2 * b ^ - 1)) ^ - 3

Mathematics

2 answers:

Vinvika [58]3 years ago

8 0

Answer:

its d

Step-by-step explanation:

ur welcome

Fudgin [204]3 years ago

4 0

Answer:

Step-by-step explanation:

$[\frac{(a^{-2}*b^{2})}{(a^{2}*b^{-1})}]^{-3}=(a^{-2-2}*b^{2+1})^{-3}\\\\\\=(a^{-4}*b^{3})^{-3}=(a^{-4})^{-3}*(b^{3})^{-3}\\\\=a^{-4*-3}*b^{3*-3}=a^{12}*b^{-9}\\\\=\frac{a^{12}}{b^{9}}$

Hint: $a^{-m}=\frac{1}{a^{m}}\\\\a^{m}*a^{n}=a^{m+n}\\\\(a^{m})^{n}=a^{mn}\\$

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Please help me out with this

AURORKA [14]

6m (m+2) = 0 is the factored form
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Steps are on paper
If you need more explanation, comment

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3 years ago

If Chris has 2 times as many nickels as quarters and they have a combined value of 210 cents, how many of each coin does he have

BlackZzzverrR [31]

Im pretty sure she has 6 quarters and 12 nickels since it it twice as much.

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$0.5 x 12 =60

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3 years ago

Solving a motion problem using a system of equations

kvasek [131]

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3 years ago

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vesna_86 [32]

Answer:

Step-by-step explanation:

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2 years ago

A woman is randomly selected from the 18–24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally

Naddik [55]

Answer:

$X \sim N(114.8,13.1)$

Where $\mu=114.8$ and $\sigma=13.1$

We are interested on this probability

$P(X>140)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

$P(z>1.924)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(114.8,13.1)$

Where $\mu=114.8$ and $\sigma=13.1$

We are interested on this probability

$P(X>140)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this: $P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)$ And we can find this probability using the complement rule:

$P(z>1.924)=1-P(z$

8 0

3 years ago