Given:
μ=106.3 minutes
σ=18.5 minutes
Need to find
P(80<x<95)=>
P(x)=Z((95-μ)/σ)-Z((80-μ)/σ)
=Z(-0.61081)-Z(-1.42162)
=0.27066-0.077568
=0.1931
Therefore probability of customers waiting between 80 and 95 minutes is 0.1931
<u>STEPS:</u>
1) set up an equation. use x as a variable
2x + 3x = 25
2) solve the equation for x:
5x = 25
x = 5
3) Now that you know the value of x, substitute it into the expression for how any girls there are, which is "3x" (since the ratio of BOYS to GIRLS is 2:3):
3x
= 3(5)
= 15
So 15 is your answer, and there are <u>15 girls in the class.</u>
Numerator of the equation is 3*nDenominator is 4*p - 5*n The equation is m = 3n/(4p-5n)
Numerator = 3*n
Denominator = 4*p - 5*n
Equation = [m = 3n/(4p-5n)]
Answer:
it would be 3
Step-by-step explanation:
anything above 5, goes to the nearest, (in this case, whole number)
so it would be 3. hope this helped
