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Papessa [141]
3 years ago
10

In a bowl, there are 3 peaches, 2 apples, 6 lemons, and 4 plums. If 1 piece of fruit is to be selected at random, what is the pr

obability it will be a lemon?
Mathematics
1 answer:
wolverine [178]3 years ago
3 0
All together there are 15 pieces of fruit
out of 15, 6 of them are lemons.
the probability that the fruit will be a lemon is
6/15
which reduces to
2/5
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Which expression shows the result of applying the distributive property to 9(2+5m)9(2+5m)
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Step-by-step explanation:


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(30 POINTS) see image and evaluate
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Step-by-step explanation:

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The difference of the range and the interquartile range of the data set represented by the box plot is
Varvara68 [4.7K]

Answer:

R - IQR = 10

Step-by-step explanation:

The interquartile range is IQR is:

IQR = Q_3 -Q_1

Where:

Q_3 = third quartile

Q_1 = first quartile

So the interquartile range is the difference between the highest quartile and the lowest quartile. In other words, it is the width of the box in the diagram.

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IQR = 29 -21\\IQR = 8

The R range is the difference between the highest value and the lowest. In other words:R = 34 -16\\R = 18

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Sin2x-sin2xcos2x=sin4x
yaroslaw [1]

It looks like the given equation is

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Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

which lets us rewrite the equation as

sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)

Move everything over to one side and factorize:

sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0

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Then we have two families of solutions,

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(where n is any integer)

[2x = 2nπ   or   2x = π + 2nπ]

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[x = nπ   or   x = π/2 + nπ]

… … …   or   [x = 1/2 arccos(1/3) + nπ   or   x = -1/2 arccos(1/3) + nπ]

7 0
2 years ago
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