12 it's adds ×÷2 ( 8÷2=4) and then add the two numbers (8&4)
The coordinates of the endpoints of line segments T'V' are; T'(-1, 2) and V'(0, 1).
<h3>What are the coordinates of the endpoints of the segment T'V'?</h3>
It follows from the task content that the transformation involved in the formation of the image from the pre-image is dilation by a scale factor of 1/4.
On this note, given that the coordinates of T and V from the task content are; (-4, 8) and (0,4), it follows that the coordinates of the endpoints as required are; T'(-1, 2) and V'(0, 1).
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G(x) when x = -3 : 4 - 3(-3) = 13
2. 4
3. -11
The bar should be 8 1/24 from the each edge of the door.
We need to subtract 10 1/4 from 26 1/3 to get the fraction of the space not covered by the towel bar.
We also need to divide the difference by 2 because we placed the towel bar in the center of the door.
1st we need to convert the mixed fractions into fractions to perform subtraction.
26 1/3 = ((26*3)+1)/3 = 79/3
10 1/4 = ((10*4)+1)/4 = 41/4
Steps in Subtracting Fractions
Step 1. Make sure the denominator is the same. 3 and 4 are the denominators, they are not the same but they are factor of 12. So,
79/3 must be multiplied by 4 = 79 * 4 / 3 * 4 = 316 / 12
41/4 must be multiplied by 3 = 41 * 3 / 4 * 3 = 123 / 12
Step 2. Subtract the numerators and place them above the common denominator
316/12 - 123/12 = 316 - 123 / 12 = 193 / 12
Before we can simplify the fraction, we must divide it by two to get the measurement of each edge of the door.
Steps in dividing fractions.
Step 1. Get the reciprocal of the 2nd fraction.
1st fraction : 193 / 12
2nd fraction : 2 /1 ⇒ reciprocal 1/2
Step 2. Multiply the 1st fraction to the reciprocal of the 2nd fraction
193 / 12 * 1/2 = 193 * 1 / 12 * 2 = 193 / 24
Step 3. Simplify the fraction.
193 / 24 = 8 1/24
Answer: A
Step-by-step explanation:
To find the inner product of two vectors (a,b) and (c,d) you would use the equation (a * c) + (b * d)
So for (7,2) and (0,-2) the inner product would be
(7 * 0) + (2 * -2)
= 4
The vectors are only perpendicular when the inner product is equal to 0. Since it is equal to -4 in this case, the vectors are not perpendicular.
A -4; no