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devlian [24]
3 years ago
10

Joshua's math textbooks weigh 43.21 ounces his social studies book weighs 38.99 ounces what is the difference in weight between

the two books
Mathematics
2 answers:
ZanzabumX [31]3 years ago
4 0
You will have to subtract 43.21 from 38.99. 43.21-38.99= 4.22
Ymorist [56]3 years ago
4 0

Answer:

the difference in weight between the two books is 4.22 ounces

Step-by-step explanation:

Hello, I think I can help you with this.s we have the same unit of measure(ounce) we can perform the subtraction directly

Step 1

Let

Joshua's math textbooks weight : 43.21 ounces

Joshua's math textbooks weight: 38.99 ounces

the difference in weight between the two books will be.

Joshua's math textbooks weight : 43.21 ounces

<h2>-</h2>

Joshua's math textbooks weight: 38.99 ounces

______________________________________

difference in weight between the two books=43.21 ounces -38.99 ounces

difference in weight between the two books=4.22 ounces

I hope it helps, have a great day.

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Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis,Exponent,Multiplication,Division,Addition,Subtraction

Step 1

3(x-4)=12  Equation/Question

Step 2

3(x-4)=12  Remove parenthesis

3x-12=12

Step 3

3x-12=12  Add 12 to sides

3x=24

Step 4

3x=24  Divide sides by 3

answer

x=8

Hope this helps

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Answer:

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Step-by-step explanation:

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Answer:

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Read 2 more answers
In a large school, it was found that 71% of students are taking a math class, 77% of student are taking an English class, and 58
Anni [7]

Answer:

P (Math or English) = 0.90

Step-by-step explanation:

* Lets study the meaning of or , and on probability

- The use of the word or means that you are calculating the probability

  that either event A or event B happened

- Both events do not have to happen

- The use of the word and, means that both event A and B have to

  happened

* The addition rules are:

# P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen

  at the same time)

# P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they  

   have at least one outcome in common)

- The union is written as A ∪ B or “A or B”.  

- The Both is written as A ∩ B or “A and B”

* Lets solve the question

- The probability of taking Math class 71%

- The probability of taking English class 77%

- The probability of taking both classes is 58%

∵ P(Math) = 71% = 0.71

∵ P(English) = 77% = 0.77

∵ P(Math and English) = 58% = 0.58

- To find P(Math or English) use the rule of non-mutually exclusive

∵ P(A or B) = P(A) + P(B) - P(A and B)

∴ P(Math or English) = P(Math) + P(English) - P(Math and English)

- Lets substitute the values of P(Math) , P(English) , P(Math and English)

 in the rule

∵ P(Math or English) = 0.71 + 0.77 - 0.58 ⇒ simplify

∴ P(Math or English) =  0.90

* P(Math or English) = 0.90

8 0
3 years ago
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