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faust18 [17]
4 years ago
14

The number of oxygen atoms (O) in 0.24g of calcium carbonate Ca CO3

Chemistry
1 answer:
Mars2501 [29]4 years ago
7 0

Answer:

4.3 × 10²¹ atoms

Explanation:

Step 1: Calculate the moles corresponding to 0.24 g of CaCO₃

The molar mass of CaCO₃ is 100.09 g/mol.

0.24 g × (1 mol/100.09 g) = 2.4 × 10⁻³ mol

Step 2: Calculate the moles of oxygen in 2.4 × 10⁻³ moles of CaCO₃

The molar ratio of CaCO₃ to O is 1:3. The moles of O are 3/1 × 2.4 × 10⁻³ mol = 7.2 × 10⁻³ mol

Step 3: Calculate the number of O atoms in 7.2 × 10⁻³ moles of O

We will use Avogadro's number: there are 6.02 × 10²³ atoms of O in 1 mole of atoms of O.

7.2 × 10⁻³ mol × (6.02 × 10²³ atoms/1 mol) = 4.3 × 10²¹ atoms

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Which of the following molecules would form a micelle?a. NaClb.CH3COOHc. CH3COO^-NH^4+d. CH3(CH2)^10COO^-Na^+e. CH3(CH2)^10CH3
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CH₃(CH₂)₁₀COONa

Explanation:

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CH₃(CH₂)₁₀COONa will form micelle . Micelle are formed by soap solution which helps in the removal of oily dirt from our clothes . They are spherical shaped tiny droplet of oil which contains the tail of long chain organic compound like salt of long chain fatty  acids . The surface of the droplet is lined with the tip of the chain which consists of negative charge of the tail end . On the average , each micelle contains a specific amount of charge . Due to it , they make colloidal solution in the water and gets washed off my water . The oily dirt is thus removed .

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3 years ago
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