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Eddi Din [679]
3 years ago
7

Sodium (na) , atomic number 11, has a tendency to lose an electron in the presence of chlorine. after losing the electron, na wi

ll have ___ protons in its nucleus
Chemistry
1 answer:
Vinvika [58]3 years ago
4 0

The atomic number is equal to number of protons present in the nucleus of an atom or vice-versa. For any atom, there is no change in number of protons either by adding or removal of electron.

Since, sodium is a metal, it has tendency to lose electron in the presence of non-metal i.e. chlorine. Thus, after lose of an electron, there is no change in the number of protons or number of protons will remain same.

Therefore, atomic number of metal is 11 which is also equal to the number of protons implies sodium will have 11 protons in its nucleus.

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Hot-air balloons float because the air caught inside the balloon is heated up by a burner, making it less dense than the air outside. As the burner heats the air, it expands and some of the air escapes; that's what makes it less dense

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A group of students created a model showing a type of matter which of the following discribes what is shows by the model?
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liquid

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5. Geologists think that the inner and outer cores of Earth consist of<br> iron and nickel.
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is this true/false? if so its true.

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The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in
olya-2409 [2.1K]

Answer:

2: Moved faster and spread farther apart.

Explanation:

Restate the question: The movement of the liquid in a thermometer shows changes in temperature. An increase in temperature indicates the molecules in the liquid.

1. moved slower and closer together.

2.moved faster and spread farther apart.

3. contracted in size when heated.

4. expanded in size when heated.

Water that is cold does not have the energy to bounce of the walls, instead it is like a group of animals they group together for the warmth of the others when it gets really cold.

So it cant be 1.

We all know that power lines sag lower on a hot day (or a tire for a car, it has increases pressure). but those are different types of molecules.

So that rules out 3 and 4.

Which leaves you with 2.

The increase in temperature causes the water molecule to gain energy and move quickly, which resulted in water molecule that are farther apart and an increase in water volume.

Hope it helps!

7 0
3 years ago
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A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The
V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 \frac{cal}{gC}.

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

  • Q is the heat exchanged by a body of mass m.
  • C is the specific heat substance.
  • ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

  • Mass of metal = 50 g
  • Initial temperature of metal= 45 °C
  • Final temperature of metal= 11.08 ºC
  • Specific heat of metal= ?

For water:

  • Mass of water = 250 g
  • Initial temperature of water= 10 ºC
  • Final temperature of water= 11.08 ºC
  • Specific heat of water = 1.035 \frac{cal}{gC}

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater=  1.035 \frac{cal}{gC} × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 \frac{cal}{gC} × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 \frac{cal}{gC} × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= \frac{279.45 cal}{1696 gC}

<u><em>Specific heat of metal= 0.165 </em></u>\frac{cal}{gC}

Finally, the specific heat of metal is 0.165 \frac{cal}{gC}.

Learn more about calorimetry:

brainly.com/question/11586486

brainly.com/question/24724338

brainly.com/question/14057615

brainly.com/question/24988785

#SPJ1

7 0
2 years ago
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