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Pachacha [2.7K]
3 years ago
10

Which of the following would lead to the smallest entropy loss in the surroundings?

Chemistry
2 answers:
PIT_PIT [208]3 years ago
7 0
I think the answer is b
Harlamova29_29 [7]3 years ago
7 0

The following would lead to the smallest entropy loss in the surroundings: A. An endothermic reaction in a hot environment.

<h3>Further explanation </h3>

An endothermic process is process that absorbs energy from its surroundings, usually in the form of heat. Whereas an exothermic reaction is a chemical reaction that releases energy through light or heat.  In an exothermic reaction, the external entropy (or entropy of the surroundings) increases. Whereas in an endothermic reaction, the external entropy (or entropy of the surroundings) decreases.

Change in entropy =  \frac{Change in thermal energy}{Temperature in Kelvin}

For the loss of entropy, change in the thermal energy must be negative. It is possible only in case of endothermic reaction, since it absorbs heat energy from the surroundings. Whereas the higher the temperature of surrounding, the lower will be change in entropy

The following would lead to the smallest entropy loss in the surroundings: A. An endothermic reaction in a hot environment.

Hope it helps! Thanks

<h3>Learn more</h3>
  1. Learn more about  An endothermic reaction brainly.com/question/12200122
  2. Learn more about An exothermic reaction brainly.com/question/1831525
  3. Learn more about  cold environment. brainly.com/question/3569739

<h3>Answer details</h3>

Grade:  9

Subject:  chemistry

Chapter:  Endothermic process

Keywords:    cold environment, endothermic reaction,  exothermic reaction, hot environment, entropy loss

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Since the density of water is greater than the density of the boat ( 1 > 0.88) then that means, the boat will NOT sink.

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To make 340mL of a 0.4 M solution of Lici, how many mL of a 8 M solution should be used?
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A 25.0 ml sample of 0.150 m hydrazoic acid is titrated with a 0.150 m naoh solution. what is the ph after 15.0 ml of the sodium
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moles NH3 = molarity * volume 

                    = 0.15 m * 0.025 L

                   =  0.00375 moles

moles NaOH = molarity * volume 

                       = 0.15 m * 0.015 L

                       = 0.00225 moles 

after that we shoul get the total volume = 0.025L + 0.015L

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So we can get the concentration of NH3 & NaOH by:

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∴[NaOH] = moles NaOH / total volume 

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then, when we have the value of Ka of NH3 so we can get the Pka value from:

Pka = -㏒Ka 

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finally, by using H-H equation we can get PH:

PH = Pka + ㏒[salt/ basic]

PH = 4.7 +㏒[0.05625/0.09375]

∴ PH = 4.48 


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