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Pachacha [2.7K]
4 years ago
10

Which of the following would lead to the smallest entropy loss in the surroundings?

Chemistry
2 answers:
PIT_PIT [208]4 years ago
7 0
I think the answer is b
Harlamova29_29 [7]4 years ago
7 0

The following would lead to the smallest entropy loss in the surroundings: A. An endothermic reaction in a hot environment.

<h3>Further explanation </h3>

An endothermic process is process that absorbs energy from its surroundings, usually in the form of heat. Whereas an exothermic reaction is a chemical reaction that releases energy through light or heat.  In an exothermic reaction, the external entropy (or entropy of the surroundings) increases. Whereas in an endothermic reaction, the external entropy (or entropy of the surroundings) decreases.

Change in entropy =  \frac{Change in thermal energy}{Temperature in Kelvin}

For the loss of entropy, change in the thermal energy must be negative. It is possible only in case of endothermic reaction, since it absorbs heat energy from the surroundings. Whereas the higher the temperature of surrounding, the lower will be change in entropy

The following would lead to the smallest entropy loss in the surroundings: A. An endothermic reaction in a hot environment.

Hope it helps! Thanks

<h3>Learn more</h3>
  1. Learn more about  An endothermic reaction brainly.com/question/12200122
  2. Learn more about An exothermic reaction brainly.com/question/1831525
  3. Learn more about  cold environment. brainly.com/question/3569739

<h3>Answer details</h3>

Grade:  9

Subject:  chemistry

Chapter:  Endothermic process

Keywords:    cold environment, endothermic reaction,  exothermic reaction, hot environment, entropy loss

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Answer:

Answer is explained in the explanation section below.

Explanation:

Penetration refers to the proximity of electrons in an orbital to the nucleus.

Deeper-penetrating electrons have less shielding and therefore a higher Effective nuclear charge (Zeff), but they better shield other electrons.

To illustrate penetration, we may use the idea of Zeff, or effective nuclear charge. It's actually the difference between the number of charged protons and the number of shielded electrons. To put it another way, how effective the nucleus is at attracting electrons. Since they do not shield themselves, the core electrons penetrate the most and are exposed to the most strong nuclear charge.

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In a multi-electron unit, the electron density near the nucleus of an atom for each shell and subshell of an electron is used to measure the nucleus penetration by an electron.

Since it has a higher electron density near the nucleus, the 2s electron penetrates the nucleus of the atom more than the 2p electron.

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5 0
3 years ago
3.) 2.46 grams of Cu(NO3)2 would contain how many formula units?
RUDIKE [14]

Answer:

7.90×10²¹ formula units

Explanation:

From the question given above, the following data were obtained:

Mass of Cu(NO₃)₂ = 2.46 g

Formula units of Cu(NO₃)₂ =?

From Avogadro's hypothesis,

1 mole of Cu(NO₃)₂ = 6.02×10²³ formula units

Next, we shall determine the mass of 1 mole of Cu(NO₃)₂. This can be obtained as follow:

1 mole of Cu(NO₃)₂ = 63.5 + 2[14 + (3×16)]

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Thus,

187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units

Finally, we shall determine the formula units contained in 2.46 g of Cu(NO₃)₂. This can be obtained as follow:

187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units.

Therefore,

2.46 g of Cu(NO₃)₂ =

(2.46 × 6.02×10²³)/187.5

= 7.90×10²¹ formula units

Thus, 2.46 g of Cu(NO₃)₂ contains 7.90×10²¹ formula units

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