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Pachacha [2.7K]
3 years ago
10

Which of the following would lead to the smallest entropy loss in the surroundings?

Chemistry
2 answers:
PIT_PIT [208]3 years ago
7 0
I think the answer is b
Harlamova29_29 [7]3 years ago
7 0

The following would lead to the smallest entropy loss in the surroundings: A. An endothermic reaction in a hot environment.

<h3>Further explanation </h3>

An endothermic process is process that absorbs energy from its surroundings, usually in the form of heat. Whereas an exothermic reaction is a chemical reaction that releases energy through light or heat.  In an exothermic reaction, the external entropy (or entropy of the surroundings) increases. Whereas in an endothermic reaction, the external entropy (or entropy of the surroundings) decreases.

Change in entropy =  \frac{Change in thermal energy}{Temperature in Kelvin}

For the loss of entropy, change in the thermal energy must be negative. It is possible only in case of endothermic reaction, since it absorbs heat energy from the surroundings. Whereas the higher the temperature of surrounding, the lower will be change in entropy

The following would lead to the smallest entropy loss in the surroundings: A. An endothermic reaction in a hot environment.

Hope it helps! Thanks

<h3>Learn more</h3>
  1. Learn more about  An endothermic reaction brainly.com/question/12200122
  2. Learn more about An exothermic reaction brainly.com/question/1831525
  3. Learn more about  cold environment. brainly.com/question/3569739

<h3>Answer details</h3>

Grade:  9

Subject:  chemistry

Chapter:  Endothermic process

Keywords:    cold environment, endothermic reaction,  exothermic reaction, hot environment, entropy loss

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13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

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Va = (2 x 39)/6

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If 88.0 L of natural gas, which is essentially methane (CH4), undergoes complete combustion at 720. mm Hg and 22ºC, how many gra
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Explanation:

Data given:

volume of the gas = 88 Liters

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The formula is used is of ideal gas law to know the number of moles of CH4 undergoing combustion.

PV = nRT

n = \frac{PV}{RT}

putting the values in the equation

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3.5 moles will give x moles of water

2/1 = x/3.5

x =  7 moles of water  (atomic mass of water = 18 gram/mole)

mass = atomic mass x number of moles

mass = 18 x 7

          =126 grams of water is formed.

7 0
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