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wolverine [178]
3 years ago
11

I how do I do this ?!??

Mathematics
1 answer:
stiv31 [10]3 years ago
5 0

Answer:

m = -3/2 and b = 4

Step-by-step explanation:

m = slope and u go down 3 and over 2 so its -3/2

b = your y intercept and its intercepting through 4 on the y-axis

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A shirt marked $320.00 was sold at a discount of 5%. What was the selling price?
Mashcka [7]

Answer:

304

Step by step:

Using your calculator 5% of 320 is 16.

Since it was a discount, you subtract 16 since you're marking it down.

320-16=304

304 is your answer

How do I know? Well, there it takes 20+20+20+20+20 to equal a hundred. We can do this same math for this problem. 16 x 20 is 320

3 0
3 years ago
Read 2 more answers
(x+5)(x+1)+(x+5)(x+8)
gtnhenbr [62]

Answer:

2x² + 19x + 45

Step-by-step explanation:

(x + 5)(x + 1) + (x + 5)(x + 8) ← expand both sets of factors using FOIL

= x² + 6x + 5 + x² + 13x + 40 ← collect like terms

= 2x² + 19x + 45

5 0
2 years ago
Five numbers has a mean of 12. When one (1) number is removed the mean is 11. What is the value of the number removed?
bonufazy [111]

Answer:

16

Step-by-step explanation:

The mean of a group of values is calculated as

mean = \frac{sum}{count}

Given 5 numbers with a mean of 12, then

\frac{sum}{5} = 12 ( multiply both sides by 5 )

sum = 60

let the number removed be x , then

\frac{60-x}{4} = 11 ( multiply both sides by 4 )

60 - x = 44 ( subtract 60 from both sides )

- x = - 16 ( multiply both sides by - 1 )

x = 16

The number removed was 16

6 0
3 years ago
Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.
KatRina [158]
AB = AU + UB = 20x + 108 + 273 = 20x + 381

\cfrac{AU}{AB} =\cfrac{UV}{BC}    \\  \\  \cfrac{20x+108}{20x+381} =\cfrac{444}{703}   \\  \\ 703(20x+108)=444(20x+381)\\\\14060x+75924=8880x+169164 \\  \\ 14060x-8880x = 169164 - 75924 \\  \\ 5180x = 93240 \\  \\ x=93240/5180 \\  \\ x=18
5 0
3 years ago
Please help, this makes no sense to me
aev [14]

Answer:

7/11

Step-by-step explanation:

Let X equal the decimal number

Equation 1:

X=0.63¯¯¯¯¯

With 2 digits in the repeating decimal group,

create a second equation by multiplying

both sides by 102 = 100

Equation 2:

100X=63.63¯¯¯¯¯

Subtract equation (1) from equation (2)

100XX99X===63.63...0.63...63

We get

99X=63

Solve for X

X=6399

Find the Greatest Common Factor (GCF) of 63 and 99, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 9,

63÷999÷9=711

Therefore

X=711

In conclusion,

0.63¯¯¯¯¯=711

used

https://www.calculatorsoup.com/calculators/math/decimal-to-fraction-calculator.php

6 0
3 years ago
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