Answer:
3. 126.02 g of H₂S and 1109.2 g of NaI
4. 364.5g of Mg
5. 361.08 g of MgSO₄ and 108 g of H₂O
Explanation:
3. This is the reaction
2HI + Na₂S → H₂S + 2NaI
7.4 moles of HI react, so, ratio is 2:1 with H₂S and 2:2 with NaI
We would produce the same moles of NaI, 7.4 moles and the half of moles, of H₂S (7.4 /2) = 3.7 moles
Let's convert the moles to mass (mol . molar mass)
3.7 mol H₂S . 34.06 g/mol = 126.02 g
7.4 mol NaI . 149.9 g/mol = 1109.2 g
4. The balanced reaction is this:
3Mg + N₂ → Mg₃N₂
Ratio is 1:3. Therefore 1 mol of Mg₃N₂ were produced by 3 moles of Mg.
So, 5 moles of Mg₃N₂ would have been produced by 15 moles of Mg. (5 .3)
Let's convert the moles to mass (moles . molar mass)
15 mol . 24.30 g/mol = 364.5 g
5. The reaction is: H₂SO₄ + Mg(OH)₂ → MgSO₄ + 2H₂O
Ratios are 1:1 and 1:2, between sulfuric acid and the products.
If I have 3 moles of acid, I would produce 3 moles of magnessium sulfate and 6 moles of water (3 .2)
Let's convert the moles to mass
3 mol . 120.36 g/mol = 361.08 g of MgSO₄
6 mol . 18 g/mol = 108 g of H₂O
