<u>Answer:</u> The increase in temperature is 7.14°C
<u>Explanation:</u>
To calculate the change in temperature, we use the equation:
where,
q = heat absorbed = 14.5 kJ = 14500 J (Conversion factor: 1 kJ = 1000 J)
m = mass of water = 485 g g
c = specific heat capacity of water = 4.184 J/g.°C
= change in temperature = ?
Putting values in above equation, we get:
Hence, the increase in temperature is 7.14°C
When the antimatter is atomic antihydrogen, a small amount of it is mixed with excess atomic hydrogen (gathered from interstellar space during flight).
<h3>What is antimatter ?</h3>
According to contemporary physics, antimatter is described as being made up of the opposite particles from "ordinary" matter, or their "partners." Only a few nanograms of antiparticles have been created artificially, but tiny quantities of antiparticles are produced every day at particle accelerators and in natural processes like cosmic ray collisions and some types of radioactive decay. However, only a small portion of these antiparticles have been successfully bound together in experiments to form antiatoms. Antimatter has never been built in a macroscopic amount due to its extremely high cost, complexity in synthesis, and handling.
A particle and its antiparticle, such as a proton and an antiproton, theoretically have the same mass but the opposite electric charge and other variations in quantum numbers.
To learn more about antimatter from the given link:
brainly.com/question/518346
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Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Answer:
17.5 g
Explanation:
Given data
- Mass of solution to be prepared: 50.0 grams
- Concentration of the salt solution: 35.0%
The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.
Answer:
yes its correct, temperature is a measure of energy particles have, the more energy the faster they move and the higher the temp
Explanation:
