Answer:
None of these
Explanation:
For a reaction;
aA + bB ------>cC + dD
The equilibrium constant K is given as;
K = [C]^c [D]^d/[A]^a [B]^b
The equilibrium constant neither depends on the concentrations of the reactants nor on that of the products.
Let us recall that at equilibrium, the concentrations of reactants and products remain largely constant. This implies that, concentration of species do not appreciably change at equilibrium because the rates of forward and reverse reactions are equal.
Hence, the equilibrium constant neither depends on the initial/final concentrations of the reactants nor on the initial/final concentrations of the products.
The mass defect refers to the amount of mass that has been converted to energy to hold the nucleus together. That means the mass defect is what you're using in your equation to calculate E.
<span>E=m<span>c2</span></span><span>E=(5.0531×<span>10<span>−29</span></span>)(3×<span>108</span><span>)2</span></span><span>E=4.55×<span>10<span>−12</span></span></span><span>
The binding energy is 4.55 x 10^(-12) J.
Let me know if you have any questions!</span>
<span>They absorb calcium ions and bicarbonate (hydrogen carbonate) ions.
Sooo B
I hope this helps! :)
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Q1) The best description for molecule b in the diagram is adenosine diphosphate because there are only two phosphate groups. (b)
Q2) I would say b again, but I am not 100% sure. In the diagram, ATP seems to have given off a phosphate group and become ADP. The other answers are all not specified in the diagram, but rather inferences from what might be happening.