Answer:
because im trynna get these 5 points
Explanation:
mklnk.m
Answer: A volume of 500 mL water is required to prepare 0.1 M
from 100 ml of 0.5 M solution.
Explanation:
Given:
= 0.1 M,
= ?
= 0.5 M,
= 100 mL
Formula used to calculate the volume of water is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M
from 100 ml of 0.5 M solution.
Density is the mass of substance per unit volume of a substance. to solve the problem, first calculate the mass of the gas.
mass gas = ( mass of balloon with gas ) - ( mass of balloon )
mass gas = 10.24 g - 2.42 g
mass gas = 7.82 g
so the density
density = m / v = 7.82 g / 5470 cm3
density = 0.00145 g / cm3