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Can u plz tell where are the statements
K₃PO₄<span>(aq) reacts with Al(NO</span>₃)₃(aq) and form AlPO₄(s) and KNO₃(aq) as the products.
Before writing net ionic reaction, following steps should be followed.
Step 1 : Write the balanced chemical equation for the reaction and indicate the state of compound as aq,s,g or l.
K₃PO₄(aq) + Al(NO₃)₃(aq) → AlPO₄(s) + 3KNO₃(aq)
Step 2 : Identify the ionic species which dissolve in water to form ions.
K₃PO₄(aq) → 3K⁺(aq) + PO₄⁻(aq)
Al(NO₃)₃(aq) → Al³⁺(aq) + 3NO₃⁻(aq)
KNO₃(aq) → K⁺(aq) + NO₃⁻(aq)
Step 3 : Write the equation again by using ions.
3K⁺(aq) + PO₄⁻(aq) + Al³⁺(aq) + 3NO₃⁻(aq) → AlPO₄(s) +3K⁺(aq) + 3NO₃⁻(aq)
Step 4 : Identify the similar species in both side of the equation and cut off them.
3K⁺(aq) and 3NO₃⁻(aq) present in both sides. Hence, those ions can be cut off.
Step 5 : Get the final ionic equation.
The net ionic equation for the given reaction is
Al³⁺(aq) + PO₄⁻(aq) → AlPO₄(s)
Answer:
CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)
Explanation:
any combustion of a hydrocarbon equation is in form:
CₓHₐ(g) + BO₂(g) ---> YCO₂(g) + ZH₂O(g), where x,a,b,y,z are all whole number positive integers
there will be 1 CO₂ to 2 H₂O, since there is 1 C to 4 H in CH₄; it is not 1:4 since 2 H is needed in H₂O
CH₄(g) + _O₂(g) ---> 1CO₂ + 2H₂O
there is 4 total O on products side, which can make 2O₂
CH₄(g) + 2O₂(g) ---> 1CO₂(g) + 2H₂O(g)
