Hi is the answer so this makes it okay to do thing when you have it
Answer:
14000
Explaination:
spwithvat = sp without vat + 13% of sp without vat
let, sp without vat be x.
sp with vat= x + 13% of x.
or, 13447 = x + 13/100 × x
or, 1344700 = 113x
or, x= 1344700/113
x = 11900
Let, mp be y.
sp with vat = mp - 15% of mp
or, 11900 = y - 15/100 × y
or, 1190000 = 85y
or, y= 1190000/85
y= 14000
Answer:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error:

For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is
We need a sample size of at least n, in which n is found M = 0.04.







With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.
Best to look up the formula for the surface area of a sphere and then find it:
A = 4πr^2, where r is the radius of the sphere. Then,
A = 4π(15 in)^2 = 4(3.14)(225 in^2) = 2826 in^2 (answer)
This is represented by the formula given in the lower left.
I can't help without a question.