Answer:
The last one if it says to add and the second one if it says to subt.
Hope this helps!!
Step-by-step explanation:
Answer:
i will help you
Step-by-step explanation:
do you have a picture of the assignment? or can you post a picture of it?
Answer:
Length = 6 inches, Width = 10 inches
Step-by-step explanation:
A rectangular roof shingle has a perimeter of 32 inches and an area of 60 square inches. What are the dimensions of the shingle?
Note :
L = Length
W = Width
The perimeter of a rectangle = 2( L + W)
The area of a rectangle = LW.
A rectangular roof shingle has a perimeter of 32 inches and an area of 60 square inches.
32 = 2( L + W)
Divide both sides by 2
16 = L + W.... Equation 1
L = 16 - W
Also:
LW = 60....... Equation 2
Let us substitute 16 - W for L in Equation 2
(16 - W)W = 60
16W - W² = 60
W² - 16W + 60 = 0
W² - 6W - 10W + 60 = 0
W(W - 6) - 10(W - 6) = 0
W - 6 = 0, W = 6 inches
W - 10 = 0, W = 10 inches
Solving for L
W = 10
L = 16 - 10
L = 6 inches
Therefore, the dimensions of the shingle =
Length = 6 inches, Width = 10 inches
Answer:
x = 8 or x = -2
Step-by-step explanation:
x^2 - 6x + 9 = 25
x^2 - 6x - 16 = 0
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
with a = 1
b = -6
c = -16
substitute in the formula
x = [-(-6) +/- √(-6^2 - 4(1)(-16))]/2(1)
x = [6 +/- √(36 + 64)]/2
x = [6 +/- √10]/2
x = [6 +/- 10]/2
x1 = [6 + 10]/2 = 16/2 = 8
x2 = [6 - 10]/2 = -4/2 = -2
